353 lines
16 KiB
VB.net
353 lines
16 KiB
VB.net
#Region "Microsoft.VisualBasic::a4d7e0eff926a6a46c5ed05c2935484d, Microsoft.VisualBasic.Core\Extensions\Math\Correlations\Ranking.vb"
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' Author:
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'
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' asuka (amethyst.asuka@gcmodeller.org)
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' xie (genetics@smrucc.org)
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' xieguigang (xie.guigang@live.com)
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'
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' Copyright (c) 2018 GPL3 Licensed
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'
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'
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' GNU GENERAL PUBLIC LICENSE (GPL3)
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'
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'
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' This program is free software: you can redistribute it and/or modify
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' it under the terms of the GNU General Public License as published by
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' the Free Software Foundation, either version 3 of the License, or
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' (at your option) any later version.
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'
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' This program is distributed in the hope that it will be useful,
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' but WITHOUT ANY WARRANTY; without even the implied warranty of
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' MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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' GNU General Public License for more details.
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'
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' You should have received a copy of the GNU General Public License
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' along with this program. If not, see <http://www.gnu.org/licenses/>.
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' /********************************************************************************/
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' Summaries:
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' Module Ranking
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'
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'
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' Enum Strategies
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'
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'
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'
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'
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'
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'
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' Function: DenseRanking, FractionalRanking, ModifiedCompetitionRanking, OrdinalRanking, Ranking
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' StandardCompetitionRanking
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'
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'
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' /********************************************************************************/
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#End Region
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Imports System.Runtime.CompilerServices
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Imports Microsoft.VisualBasic.Linq
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Namespace Math.Correlations
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''' <summary>
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''' A **ranking** is a relationship between a set of items such that, for any two items,
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''' the first is either 'ranked higher than', 'ranked lower than' or 'ranked equal to'
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''' the second. In mathematics, this is known as a weak order or total preorder of objects.
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''' It is not necessarily a total order of objects because two different objects can have
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''' the same ranking. The rankings themselves are totally ordered. For example, materials
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''' are totally preordered by hardness, while degrees of hardness are totally ordered.
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'''
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''' > https://en.wikipedia.org/wiki/Ranking
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''' </summary>
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Public Module Ranking
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''' <summary>
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''' ###### Strategies for assigning rankings
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'''
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''' It is not always possible to assign rankings uniquely. For example, in a race
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''' or competition two (or more) entrants might tie for a place in the ranking.
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''' When computing an ordinal measurement, two (or more) of the quantities being
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''' ranked might measure equal. In these cases, one of the strategies shown below
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''' for assigning the rankings may be adopted. A common shorthand way to distinguish
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''' these ranking strategies is by the ranking numbers that would be produced for
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''' four items, with the first item ranked ahead of the second and third (which
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''' compare equal) which are both ranked ahead of the fourth.
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''' </summary>
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Public Enum Strategies As Integer
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StandardCompetition = 1224
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ModifiedCompetition = 1334
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DenseRanking = 1223
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OrdinalRanking = 1234
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FractionalRanking = 1 + 2.5 + 2.5 + 4
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End Enum
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''' <summary>
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''' 函数返回与输入的序列中的元素相同顺序的排序的得分
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''' </summary>
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''' <typeparam name="C"></typeparam>
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''' <param name="list"></param>
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''' <param name="strategy"></param>
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''' <param name="desc"></param>
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''' <returns></returns>
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<MethodImpl(MethodImplOptions.AggressiveInlining)>
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<Extension>
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Public Function Ranking(Of C As IComparable)(list As IEnumerable(Of C), Optional strategy As Strategies = Strategies.OrdinalRanking, Optional desc As Boolean = False) As Double()
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If strategy = Strategies.OrdinalRanking Then
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Return list.OrdinalRanking(desc)
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ElseIf strategy = Strategies.DenseRanking Then
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Return list.DenseRanking(desc)
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ElseIf strategy = Strategies.FractionalRanking Then
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Return list.FractionalRanking(desc)
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ElseIf strategy = Strategies.StandardCompetition Then
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Return list.StandardCompetitionRanking(desc)
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ElseIf strategy = Strategies.ModifiedCompetition Then
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Return list.ModifiedCompetitionRanking(desc)
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Else
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Throw New NotImplementedException
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End If
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End Function
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''' <summary>
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''' ###### Modified competition ranking ("1334" ranking)
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'''
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''' Sometimes, competition ranking is done by leaving the gaps in the ranking numbers before the sets
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''' of equal-ranking items (rather than after them as in standard competition ranking).[where?] The
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''' number of ranking numbers that are left out in this gap remains one less than the number of items that
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''' compared equal. Equivalently, each item's ranking number is equal to the number of items ranked equal
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''' to it or above it. This ranking ensures that a competitor only comes second if they score higher than
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''' all but one of their opponents, third if they score higher than all but two of their opponents, etc.
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'''
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''' Thus if A ranks ahead of B and C (which compare equal) which are both ranked head of D, then A gets
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''' ranking number 1 ("first"), B gets ranking number 3 ("joint third"), C also gets ranking number 3
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''' ("joint third") and D gets ranking number 4 ("fourth"). In this case, nobody would get ranking number
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''' 2 ("second") and that would be left as a gap.
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''' </summary>
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''' <typeparam name="C"></typeparam>
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''' <param name="list"></param>
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''' <returns></returns>
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<Extension> Public Function ModifiedCompetitionRanking(Of C As IComparable)(list As IEnumerable(Of C), Optional desc As Boolean = False) As Double()
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Dim array = list _
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.SeqIterator _
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.ToDictionary(Function(x) x,
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Function(i) i.i)
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Dim asc() = array _
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.Keys _
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.Sort(Function(x) x.value, desc) _
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.ToArray
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Dim ranks#() = New Double(asc.Length - 1) {}
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Dim rank% = 0
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Dim gaps = array _
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.Keys _
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.GroupBy(Function(x) x.value) _
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.ToDictionary(Function(x) x.First.value,
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Function(g)
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Return g.Count
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End Function)
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' 使用Nothing的时候，对于数字而言，会是0，则会和0冲突，
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' 使用最大的值则完全可以避免这个问题了
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Dim previous As C = asc.Last.value
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For i As Integer = 0 To asc.Length - 1
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' obj -> original_i -> rank
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With asc(i)
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If .value.CompareTo(previous) = 0 Then
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' rank += 0
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ElseIf gaps.ContainsKey(.value) Then
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previous = .value
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rank += gaps(.value)
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Else
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rank += 1
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End If
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End With
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ranks(array(asc(i))) = rank
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Next
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Return ranks
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End Function
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''' <summary>
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''' ###### Standard competition ranking ("1224" ranking)
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'''
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''' In competition ranking, items that compare equal receive the same ranking number, and then a gap
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''' is left in the ranking numbers. The number of ranking numbers that are left out in this gap is
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''' one less than the number of items that compared equal. Equivalently, each item's ranking number
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''' is 1 plus the number of items ranked above it. This ranking strategy is frequently adopted for
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''' competitions, as it means that if two (or more) competitors tie for a position in the ranking,
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''' the position of all those ranked below them is unaffected (i.e., a competitor only comes second if
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''' exactly one person scores better than them, third if exactly two people score better than them,
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''' fourth if exactly three people score better than them, etc.).
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'''
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''' Thus if A ranks ahead of B and C (which compare equal) which are both ranked ahead of D, then A
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''' gets ranking number 1 ("first"), B gets ranking number 2 ("joint second"), C also gets ranking
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''' number 2 ("joint second") and D gets ranking number 4 ("fourth").
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''' </summary>
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''' <typeparam name="C"></typeparam>
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''' <param name="list"></param>
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''' <returns></returns>
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<Extension> Public Function StandardCompetitionRanking(Of C As IComparable)(list As IEnumerable(Of C), Optional desc As Boolean = False) As Double()
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Dim array = list _
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.SeqIterator _
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.ToDictionary(Function(x) x,
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Function(i) i.i)
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Dim asc() = array _
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.Keys _
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.Sort(Function(x) x.value, desc) _
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.ToArray
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Dim ranks#() = New Double(asc.Length - 1) {}
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Dim rank% = 1
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Dim gap% = 1
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For i As Integer = 0 To asc.Length - 2
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With asc(i)
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' obj -> original_i -> rank
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ranks(array(asc(i))) = rank
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If .value.CompareTo(asc(i + 1).value) <> 0 Then
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rank += gap
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gap = 1
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Else
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gap += 1
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End If
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End With
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Next
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ranks(array(asc.Last)) = rank
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Return ranks
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End Function
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''' <summary>
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''' ###### Dense ranking ("1223" ranking)
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'''
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''' In dense ranking, items that compare equal receive the same ranking number, and the next item(s)
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''' receive the immediately following ranking number. Equivalently, each item's ranking number is 1
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''' plus the number of items ranked above it that are distinct with respect to the ranking order.
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'''
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''' Thus if A ranks ahead of B and C (which compare equal) which are both ranked ahead of D, then A
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''' gets ranking number 1 ("first"), B gets ranking number 2 ("joint second"), C also gets ranking
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''' number 2 ("joint second") and D gets ranking number 3 ("third").
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''' </summary>
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''' <typeparam name="C"></typeparam>
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''' <param name="list"></param>
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''' <returns></returns>
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<Extension> Public Function DenseRanking(Of C As IComparable)(list As IEnumerable(Of C), Optional desc As Boolean = False) As Double()
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Dim array = list _
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.SeqIterator _
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.ToDictionary(Function(x) x,
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Function(i) i.i)
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Dim asc() = array _
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.Keys _
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.Sort(Function(x) x.value, desc) _
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.ToArray
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Dim ranks#() = New Double(asc.Length - 1) {}
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Dim rank% = 1
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For i As Integer = 0 To asc.Length - 2
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With asc(i)
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' obj -> original_i -> rank
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ranks(array(asc(i))) = rank
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If .value.CompareTo(asc(i + 1).value) <> 0 Then
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rank += 1
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End If
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End With
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Next
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ranks(array(asc.Last)) = rank
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Return ranks
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End Function
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''' <summary>
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''' ###### Ordinal ranking ("1234" ranking)
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'''
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''' In ordinal ranking, all items receive distinct ordinal numbers, including items that compare equal.
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''' The assignment of distinct ordinal numbers to items that compare equal can be done at random,
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''' or arbitrarily, but it is generally preferable to use a system that is arbitrary but consistent,
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''' as this gives stable results if the ranking is done multiple times. An example of an arbitrary but
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''' consistent system would be to incorporate other attributes into the ranking order (such as
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''' alphabetical ordering of the competitor's name) to ensure that no two items exactly match.
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'''
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''' With this strategy, if A ranks ahead of B and C (which compare equal) which are both ranked ahead of D,
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''' then A gets ranking number 1 ("first") and D gets ranking number 4 ("fourth"), and either B gets
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''' ranking number 2 ("second") and C gets ranking number 3 ("third") or C gets ranking number 2 ("second")
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''' and B gets ranking number 3 ("third").
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'''
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''' In computer data processing, ordinal ranking is also referred to as "row numbering".
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''' </summary>
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''' <typeparam name="C"></typeparam>
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''' <param name="list"></param>
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''' <returns></returns>
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<Extension> Public Function OrdinalRanking(Of C As IComparable)(list As IEnumerable(Of C), Optional desc As Boolean = False) As Double()
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Dim array = list _
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.SeqIterator _
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.ToDictionary(Function(x) x,
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Function(i) i.i)
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Dim asc() = array _
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.Keys _
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.Sort(Function(x) x.value, desc) _
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.ToArray
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Dim ranks#() = New Double(asc.Length - 1) {}
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Dim rank% = 1
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For i As Integer = 0 To asc.Length - 1
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' obj -> original_i -> rank
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ranks(array(asc(i))) = rank
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rank += 1
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Next
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Return ranks
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End Function
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''' <summary>
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''' ###### Fractional ranking ("1 2.5 2.5 4" ranking)
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'''
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''' Items that compare equal receive the same ranking number, which is the mean
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''' of what they would have under ordinal rankings. Equivalently, the ranking
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''' number of 1 plus the number of items ranked above it plus half the number
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''' of items equal to it. This strategy has the property that the sum of the
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''' ranking numbers is the same as under ordinal ranking. For this reason, it
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''' is used in computing Borda counts and in statistical tests (see below).
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'''
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''' Thus if A ranks ahead of B and C (which compare equal) which are both ranked
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''' ahead of D, then A gets ranking number 1 ("first"), B and C each get ranking
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''' number 2.5 (average of "joint second/third") and D gets ranking number 4
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''' ("fourth").
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'''
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''' Here is an example: Suppose you have the data set 1.0, 1.0, 2.0, 3.0, 3.0, 4.0, 5.0, 5.0, 5.0.
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''' The ordinal ranks are 1, 2, 3, 4, 5, 6, 7, 8, 9.
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''' For v = 1.0, the fractional rank is the average of the ordinal ranks: (1 + 2) / 2 = 1.5.
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''' In a similar manner, for v = 5.0, the fractional rank is (7 + 8 + 9) / 3 = 8.0.
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''' Thus the fractional ranks are: 1.5, 1.5, 3.0, 4.5, 4.5, 6.0, 8.0, 8.0, 8.0
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''' </summary>
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''' <typeparam name="C"></typeparam>
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''' <param name="list"></param>
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''' <returns></returns>
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<Extension> Public Function FractionalRanking(Of C As IComparable)(list As IEnumerable(Of C), Optional desc As Boolean = False) As Double()
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Dim vector As C() = list.ToArray
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Dim array As SeqValue(Of C)() = vector.SeqIterator.ToArray
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Dim ranks#() = vector.OrdinalRanking(desc)
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Dim equals = array.GroupBy(Function(x) x.value)
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For Each g As IGrouping(Of C, SeqValue(Of C)) In equals
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Dim avgRanks# = Aggregate i
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In g
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Into Average(ranks(i))
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For Each i As SeqValue(Of C) In g
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ranks(i.i) = avgRanks
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Next
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Next
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Return ranks
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End Function
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End Module
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End Namespace
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