!22376 fix api format errors
Merge pull request !22376 from yingchen/code_docs_api3
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a1b6ba77ee
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@ -2734,7 +2734,7 @@ class TruncateDiv(_MathBinaryOp):
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class TruncateMod(_MathBinaryOp):
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"""
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r"""
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Returns the remainder of division element-wise.
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Inputs of `x` and `y` comply with the implicit type conversion rules to make the data types consistent.
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@ -2749,7 +2749,7 @@ class TruncateMod(_MathBinaryOp):
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- When NUM exceeds 2048 , the accuracy of operator cannot guarantee the requirement of
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double thousandths in the mini form.
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- Due to different architectures, the calculation results of this operator on NPU and CPU may be inconsistent.
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- If shape is expressed as (D1,D2... ,Dn), then D1*D2... *DN<=1000000,n<=8.
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- If shape is expressed as (D1,D2... ,Dn), then D1\*D2... \*DN<=1000000,n<=8.
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Inputs:
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- **x** (Union[Tensor, Number, bool]) - The first input is a number, or a bool,
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@ -2778,7 +2778,7 @@ class TruncateMod(_MathBinaryOp):
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class Mod(_MathBinaryOp):
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"""
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r"""
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Computes the remainder of dividing the first input tensor by the second input tensor element-wise.
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Inputs of `x` and `y` comply with the implicit type conversion rules to make the data types consistent.
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@ -2795,7 +2795,7 @@ class Mod(_MathBinaryOp):
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- When NUM exceeds 2048 , the accuracy of operator cannot guarantee the requirement of
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double thousandths in the mini form.
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- Due to different architectures, the calculation results of this operator on NPU and CPU may be inconsistent.
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- If shape is expressed as (D1,D2... ,Dn), then D1*D2... *DN<=1000000,n<=8.
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- If shape is expressed as (D1,D2... ,Dn), then D1\*D2... \*DN<=1000000,n<=8.
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Inputs:
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- **x** (Union[Tensor, Number]) - The first input is a number or a tensor whose data type is number.
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@ -2873,7 +2873,7 @@ class Floor(PrimitiveWithInfer):
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class FloorMod(_MathBinaryOp):
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"""
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r"""
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Computes the remainder of division element-wise. It's a flooring divide.
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E.g. :math:`floor(x / y) * y + mod(x, y) = x`.
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@ -2895,7 +2895,7 @@ class FloorMod(_MathBinaryOp):
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- When NUM exceeds 2048 , the accuracy of operator cannot guarantee the requirement of
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double thousandths in the mini form.
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- Due to different architectures, the calculation results of this operator on NPU and CPU may be inconsistent.
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- If shape is expressed as (D1,D2... ,Dn), then D1*D2... *DN<=1000000,n<=8.
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- If shape is expressed as (D1,D2... ,Dn), then D1\*D2... \*DN<=1000000,n<=8.
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Inputs:
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- **x** (Union[Tensor, Number, bool]) - The first input is a number or
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