llvm-project/llvm/test/Transforms/ScalarRepl/2009-03-04-MemCpyAlign.ll

20 lines
856 B
LLVM

; The store into %p should end up with a known alignment of 1, since the memcpy
; is only known to access it with 1-byte alignment.
; RUN: opt < %s -scalarrepl -S | grep "store i16 1, .*, align 1"
; PR3720
target datalayout = "E-p:64:64:64-i1:8:8-i8:8:8-i16:16:16-i32:32:32-i64:32:64-f32:32:32-f64:64:64-v64:64:64-v128:128:128-a0:0:64"
%struct.st = type { i16 }
define void @f(i8* %p) nounwind {
entry:
%s = alloca %struct.st, align 4 ; <%struct.st*> [#uses=2]
%0 = getelementptr %struct.st* %s, i32 0, i32 0 ; <i16*> [#uses=1]
store i16 1, i16* %0, align 4
%s1 = bitcast %struct.st* %s to i8* ; <i8*> [#uses=1]
call void @llvm.memcpy.p0i8.p0i8.i32(i8* %p, i8* %s1, i32 2, i32 1, i1 false)
ret void
}
declare void @llvm.memcpy.p0i8.p0i8.i32(i8* nocapture, i8* nocapture, i32, i32, i1) nounwind