llvm-project/flang/test/Semantics/resolve96.f90

63 lines
1.9 KiB
Fortran

! RUN: %S/test_errors.sh %s %t %f18
! Check distinguishability for specific procedures of defined operators and
! assignment. These are different from names because there a normal generic
! is invoked the same way as a type-bound generic.
! E.g. for a generic name like 'foo', the generic name is invoked as 'foo(x, y)'
! while the type-bound generic is invoked as 'x%foo(y)'.
! But for 'operator(.foo.)', it is 'x .foo. y' in either case.
! So to check the specifics of 'operator(.foo.)' we have to consider all
! definitions of it visible in the current scope.
! One operator(.foo.) comes from interface-stmt, the other is type-bound.
module m1
type :: t1
contains
procedure, pass :: p => s1
generic :: operator(.foo.) => p
end type
type :: t2
end type
!ERROR: Generic 'OPERATOR(.foo.)' may not have specific procedures 's2' and 't1%p' as their interfaces are not distinguishable
interface operator(.foo.)
procedure :: s2
end interface
contains
integer function s1(x1, x2)
class(t1), intent(in) :: x1
class(t2), intent(in) :: x2
end
integer function s2(x1, x2)
class(t1), intent(in) :: x1
class(t2), intent(in) :: x2
end
end module
! assignment(=) as type-bound generic in each type
module m2
type :: t1
integer :: n
contains
procedure, pass(x1) :: p1 => s1
!ERROR: Generic 'assignment(=)' may not have specific procedures 't1%p1' and 't2%p2' as their interfaces are not distinguishable
generic :: assignment(=) => p1
end type
type :: t2
integer :: n
contains
procedure, pass(x2) :: p2 => s2
generic :: assignment(=) => p2
end type
contains
subroutine s1(x1, x2)
class(t1), intent(out) :: x1
class(t2), intent(in) :: x2
x1%n = x2%n + 1
end subroutine
subroutine s2(x1, x2)
class(t1), intent(out) :: x1
class(t2), intent(in) :: x2
x1%n = x2%n + 2
end subroutine
end module