forked from OSchip/llvm-project
126 lines
3.6 KiB
ArmAsm
126 lines
3.6 KiB
ArmAsm
// This file is dual licensed under the MIT and the University of Illinois Open
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// Source Licenses. See LICENSE.TXT for details.
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#include "../assembly.h"
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// du_int __umoddi3(du_int a, du_int b);
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// result = remainder of a / b.
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// both inputs and the output are 64-bit unsigned integers.
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// This will do whatever the underlying hardware is set to do on division by zero.
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// No other exceptions are generated, as the divide cannot overflow.
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//
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// This is targeted at 32-bit x86 *only*, as this can be done directly in hardware
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// on x86_64. The performance goal is ~40 cycles per divide, which is faster than
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// currently possible via simulation of integer divides on the x87 unit.
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//
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// Stephen Canon, December 2008
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#ifdef __i386__
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.text
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.align 4
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DEFINE_COMPILERRT_FUNCTION(__umoddi3)
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pushl %ebx
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movl 20(%esp), %ebx // Find the index i of the leading bit in b.
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bsrl %ebx, %ecx // If the high word of b is zero, jump to
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jz 9f // the code to handle that special case [9].
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/* High word of b is known to be non-zero on this branch */
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movl 16(%esp), %eax // Construct bhi, containing bits [1+i:32+i] of b
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shrl %cl, %eax // Practically, this means that bhi is given by:
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shrl %eax //
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notl %ecx // bhi = (high word of b) << (31 - i) |
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shll %cl, %ebx // (low word of b) >> (1 + i)
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orl %eax, %ebx //
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movl 12(%esp), %edx // Load the high and low words of a, and jump
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movl 8(%esp), %eax // to [2] if the high word is larger than bhi
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cmpl %ebx, %edx // to avoid overflowing the upcoming divide.
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jae 2f
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/* High word of a is greater than or equal to (b >> (1 + i)) on this branch */
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divl %ebx // eax <-- qs, edx <-- r such that ahi:alo = bs*qs + r
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pushl %edi
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notl %ecx
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shrl %eax
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shrl %cl, %eax // q = qs >> (1 + i)
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movl %eax, %edi
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mull 20(%esp) // q*blo
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movl 12(%esp), %ebx
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movl 16(%esp), %ecx // ECX:EBX = a
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subl %eax, %ebx
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sbbl %edx, %ecx // ECX:EBX = a - q*blo
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movl 24(%esp), %eax
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imull %edi, %eax // q*bhi
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subl %eax, %ecx // ECX:EBX = a - q*b
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jnc 1f // if positive, this is the result.
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addl 20(%esp), %ebx // otherwise
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adcl 24(%esp), %ecx // ECX:EBX = a - (q-1)*b = result
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1: movl %ebx, %eax
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movl %ecx, %edx
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popl %edi
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popl %ebx
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retl
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2: /* High word of a is greater than or equal to (b >> (1 + i)) on this branch */
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subl %ebx, %edx // subtract bhi from ahi so that divide will not
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divl %ebx // overflow, and find q and r such that
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//
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// ahi:alo = (1:q)*bhi + r
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//
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// Note that q is a number in (31-i).(1+i)
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// fix point.
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pushl %edi
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notl %ecx
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shrl %eax
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orl $0x80000000, %eax
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shrl %cl, %eax // q = (1:qs) >> (1 + i)
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movl %eax, %edi
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mull 20(%esp) // q*blo
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movl 12(%esp), %ebx
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movl 16(%esp), %ecx // ECX:EBX = a
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subl %eax, %ebx
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sbbl %edx, %ecx // ECX:EBX = a - q*blo
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movl 24(%esp), %eax
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imull %edi, %eax // q*bhi
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subl %eax, %ecx // ECX:EBX = a - q*b
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jnc 3f // if positive, this is the result.
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addl 20(%esp), %ebx // otherwise
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adcl 24(%esp), %ecx // ECX:EBX = a - (q-1)*b = result
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3: movl %ebx, %eax
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movl %ecx, %edx
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popl %edi
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popl %ebx
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retl
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9: /* High word of b is zero on this branch */
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movl 12(%esp), %eax // Find qhi and rhi such that
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movl 16(%esp), %ecx //
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xorl %edx, %edx // ahi = qhi*b + rhi with 0 ≤ rhi < b
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divl %ecx //
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movl %eax, %ebx //
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movl 8(%esp), %eax // Find rlo such that
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divl %ecx //
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movl %edx, %eax // rhi:alo = qlo*b + rlo with 0 ≤ rlo < b
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popl %ebx //
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xorl %edx, %edx // and return 0:rlo
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retl //
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#endif // __i386__
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