When performing template argument deduction against a template-id,

only keep deduction results for successful deductions, so that they
can be compared against each other. Fixes PR8462, from Richard Smith!

llvm-svn: 117983
This commit is contained in:
Douglas Gregor 2010-11-02 00:02:34 +00:00
parent 5c86d22e67
commit e0f7a8ace9
2 changed files with 31 additions and 2 deletions

View File

@ -721,6 +721,8 @@ DeduceTemplateArguments(Sema &S,
llvm::SmallVector<const RecordType *, 8> ToVisit;
ToVisit.push_back(RecordT);
bool Successful = false;
llvm::SmallVectorImpl<DeducedTemplateArgument> DeducedOrig(0);
DeducedOrig = Deduced;
while (!ToVisit.empty()) {
// Retrieve the next class in the inheritance hierarchy.
const RecordType *NextT = ToVisit.back();
@ -738,9 +740,14 @@ DeduceTemplateArguments(Sema &S,
QualType(NextT, 0), Info, Deduced);
// If template argument deduction for this base was successful,
// note that we had some success.
if (BaseResult == Sema::TDK_Success)
// note that we had some success. Otherwise, ignore any deductions
// from this base class.
if (BaseResult == Sema::TDK_Success) {
Successful = true;
DeducedOrig = Deduced;
}
else
Deduced = DeducedOrig;
}
// Visit base classes

View File

@ -101,3 +101,25 @@ void test_f4(D d, E e, F f, G g) {
C<int, 1> *ci3c = f4c(&g);
int *ip1 = f4c(&f);
}
// PR8462
namespace N {
struct T0;
struct T1;
template<typename X, typename Y> struct B {};
struct J : B<T0,T0> {};
struct K : B<T1,T1> {};
struct D : J, K {};
template<typename X, typename Y> void F(B<Y,X>);
void test()
{
D d;
N::F<T0>(d); // Fails
N::F<T1>(d); // OK
}
}