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[asan] make LargeOOBInMemset test resistant to clever compiler optimizations 

llvm-svn: 171223
This commit is contained in:
Kostya Serebryany 2012-12-29 14:42:48 +00:00
parent 19e8beaad6
commit 9756e2e0b3
1 changed files with 4 additions and 3 deletions
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7
compiler-rt/lib/asan/tests/asan_test.cc
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@ -925,7 +925,7 @@ TEST(AddressSanitizer, MemSetOOBTest) {
// Try to allocate two arrays of 'size' bytes that are near each other.
// Strictly speaking we are not guaranteed to find such two pointers,
// but given the structure of asan's allocator we will.
static bool AllocateTwoAjacentArrays(char **x1, char **x2, size_t size) {
static bool AllocateTwoAdjacentArrays(char **x1, char **x2, size_t size) {
vector<char *> v;
bool res = false;
for (size_t i = 0; i < 1000U && !res; i++) {
@ -954,11 +954,12 @@ static bool AllocateTwoAjacentArrays(char **x1, char **x2, size_t size) {
TEST(AddressSanitizer, LargeOOBInMemset) {
for (size_t size = 200; size < 100000; size += size / 2) {
char *x1, *x2;
if (!AllocateTwoAjacentArrays(&x1, &x2, size))
if (!Ident(AllocateTwoAdjacentArrays)(&x1, &x2, size))
continue;
// fprintf(stderr, " large oob memset: %p %p %zd\n", x1, x2, size);
// Do a memset on x1 with huge out-of-bound access that will end up in x2.
EXPECT_DEATH(memset(x1, 0, size * 2), "is located 0 bytes to the right");
EXPECT_DEATH(Ident(memset)(x1, 0, size * 2),
"is located 0 bytes to the right");
delete [] x1;
delete [] x2;
return;