Fix shl to produce the correct result when the bitwidth is > 64 and the

shift amount is 0. Previously this code would do a lshr by the bit width
which can lead to incorrect results.

llvm-svn: 37010
This commit is contained in:
Reid Spencer 2007-05-12 18:01:57 +00:00
parent 5d22b630af
commit 81ee020f64
1 changed files with 6 additions and 0 deletions

View File

@ -1199,6 +1199,12 @@ APInt APInt::shl(uint32_t shiftAmt) const {
if (shiftAmt == BitWidth)
return APInt(BitWidth, 0);
// If none of the bits are shifted out, the result is *this. This avoids a
// lshr by the words size in the loop below which can produce incorrect
// results. It also avoids the expensive computation below for a common case.
if (shiftAmt == 0)
return *this;
// Create some space for the result.
uint64_t * val = new uint64_t[getNumWords()];