Bugfix: don't assert if someone manages to declare an operator new/delete template before the builtin operator new/delete.

llvm-svn: 210230
This commit is contained in:
Richard Smith 2014-06-05 00:43:02 +00:00
parent ad81f0f419
commit 599bed75ed
2 changed files with 6 additions and 3 deletions

View File

@ -1041,8 +1041,9 @@ RValue CodeGenFunction::EmitBuiltinNewDeleteCall(const FunctionProtoType *Type,
DeclarationName Name = Ctx.DeclarationNames
.getCXXOperatorName(IsDelete ? OO_Delete : OO_New);
for (auto *Decl : Ctx.getTranslationUnitDecl()->lookup(Name))
if (Ctx.hasSameType(cast<FunctionDecl>(Decl)->getType(), QualType(Type, 0)))
return EmitNewDeleteCall(*this, cast<FunctionDecl>(Decl), Type, Args);
if (auto *FD = dyn_cast<FunctionDecl>(Decl))
if (Ctx.hasSameType(FD->getType(), QualType(Type, 0)))
return EmitNewDeleteCall(*this, cast<FunctionDecl>(Decl), Type, Args);
llvm_unreachable("predeclared global operator new/delete is missing");
}

View File

@ -2,6 +2,9 @@
typedef __typeof__(sizeof(0)) size_t;
// Declare an 'operator new' template to tickle a bug in __builtin_operator_new.
template<typename T> void *operator new(size_t, int (*)(T));
// Ensure that this declaration doesn't cause operator new to lose its
// 'noalias' attribute.
void *operator new[](size_t);
@ -33,7 +36,6 @@ void *operator new[](size_t, const std::nothrow_t &) throw();
void operator delete(void *, const std::nothrow_t &) throw();
void operator delete[](void *, const std::nothrow_t &) throw();
void t2(int* a) {
int* b = new (a) int;
}