[analyzer] sprintf is a taint propagator not a source

Due to a typo, `sprintf()` was recognized as a taint source instead of a
taint propagator. It was because an empty taint source list - which is
the first parameter of the `TaintPropagationRule` - encoded the
unconditional taint sources.
This typo effectively turned the `sprintf()` into an unconditional taint
source.

This patch fixes that typo and demonstrated the correct behavior with
tests.

Reviewed By: martong

Differential Revision: https://reviews.llvm.org/D112558
This commit is contained in:
Balazs Benics 2021-10-28 11:03:02 +02:00
parent 30bd11fab4
commit 49285f43e5
2 changed files with 11 additions and 1 deletions

View File

@ -514,7 +514,7 @@ GenericTaintChecker::TaintPropagationRule::getTaintPropagationRule(
if (OneOf("snprintf"))
return {{1}, {0, ReturnValueIndex}, VariadicType::Src, 3};
if (OneOf("sprintf"))
return {{}, {0, ReturnValueIndex}, VariadicType::Src, 2};
return {{1}, {0, ReturnValueIndex}, VariadicType::Src, 2};
if (OneOf("strcpy", "stpcpy", "strcat"))
return {{1}, {0, ReturnValueIndex}};
if (OneOf("bcopy"))

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@ -341,6 +341,16 @@ void constraintManagerShouldTreatAsOpaque(int rhs) {
*(volatile int *) 0; // no-warning
}
int sprintf_is_not_a_source(char *buf, char *msg) {
int x = sprintf(buf, "%s", msg); // no-warning
return 1 / x; // no-warning: 'sprintf' is not a taint source
}
int sprintf_propagates_taint(char *buf, char *msg) {
scanf("%s", msg);
int x = sprintf(buf, "%s", msg); // propagate taint!
return 1 / x; // expected-warning {{Division by a tainted value, possibly zero}}
}
// Test configuration
int mySource1();