[LV] Simplify lambda in all_of to directly return hasVF() result. (NFC)

The if in the lambda is not necessary. We can directly return the result
of hasVF.

llvm/lib/Transforms/Vectorize/LoopVectorizationPlanner.h

@@ -274,9 +274,7 @@ public:
   bool hasPlanWithVFs(const ArrayRef<ElementCount> VFs) const {
     return any_of(VPlans, [&](const VPlanPtr &Plan) {
       return all_of(VFs, [&](const ElementCount &VF) {
-        if (Plan->hasVF(VF))
-          return true;
-        return false;
+        return Plan->hasVF(VF);
       });
     });
   }