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Fix a nondeterministic bug in APInt::roundToDouble; 

when !isSingleWord() but getActiveBits() is small,
we were using the pointer value instead of the low
word of the integer value.

llvm-svn: 78821
This commit is contained in:
Dale Johannesen 2009-08-12 17:42:34 +00:00
parent cecfe61cd1
commit 34c08bbbf9
1 changed files with 2 additions and 2 deletions
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4
llvm/lib/Support/APInt.cpp
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@ -897,10 +897,10 @@ double APInt::roundToDouble(bool isSigned) const {
// Handle the simple case where the value is contained in one uint64_t.
if (isSingleWord() || getActiveBits() <= APINT_BITS_PER_WORD) {
if (isSigned) {
int64_t sext = (int64_t(VAL) << (64-BitWidth)) >> (64-BitWidth);
int64_t sext = (int64_t(getWord(0)) << (64-BitWidth)) >> (64-BitWidth);
return double(sext);
} else
return double(VAL);
return double(getWord(0));
}
// Determine if the value is negative.