[flang] Save CallStmt::typedCall (flang-compiler/f18#879)

When `ExpressionAnalyzer::AnalyzeCall` processed a subroutine it was
always returning std::nullopt. Change it to return a `ProcedureRef`
wrapped in an `Expr` so that it can be saved in `CallStmt::typedCall`.

Original-commit: flang-compiler/f18@2cc226f66e
Reviewed-on: https://github.com/flang-compiler/f18/pull/879
This commit is contained in:
Tim Keith 2019-12-19 09:52:15 -08:00 committed by GitHub
parent b200b244f6
commit 2e9633125e
1 changed files with 9 additions and 5 deletions

View File

@ -1822,9 +1822,9 @@ MaybeExpr ExpressionAnalyzer::Analyze(
}
void ExpressionAnalyzer::Analyze(const parser::CallStmt &callStmt) {
auto expr{AnalyzeCall(callStmt.v, true)};
if (auto *procRef{UnwrapExpr<ProcedureRef>(expr)}) {
callStmt.typedCall.reset(new ProcedureRef{*procRef});
MaybeExpr expr{AnalyzeCall(callStmt.v, true)};
if (const auto *proc{UnwrapExpr<ProcedureRef>(expr)}) {
callStmt.typedCall.reset(new ProcedureRef{*proc});
}
}
@ -1840,8 +1840,12 @@ MaybeExpr ExpressionAnalyzer::AnalyzeCall(
GetCalleeAndArguments(std::get<parser::ProcedureDesignator>(call.t),
analyzer.GetActuals(), isSubroutine)}) {
if (isSubroutine) {
CheckCall(call.source, callee->procedureDesignator, callee->arguments);
// TODO: Package the subroutine call as an expr in the parse tree
if (CheckCall(
call.source, callee->procedureDesignator, callee->arguments)) {
return Expr<SomeType>{
ProcedureRef{std::move(callee->procedureDesignator),
std::move(callee->arguments)}};
}
} else {
return MakeFunctionRef(call.source,
std::move(callee->procedureDesignator),