RP18408: If a member template is used as a template template argument, it does

not cause the template specialization to have no linkage.

llvm-svn: 198726
This commit is contained in:
Richard Smith 2014-01-08 01:51:59 +00:00
parent 360a1434f0
commit 26d11be738
2 changed files with 16 additions and 1 deletions

View File

@ -782,11 +782,18 @@ static LinkageInfo getLVForClassMember(const NamedDecl *D,
// really have linkage, but it's convenient to say they do for the
// purposes of calculating linkage of pointer-to-data-member
// template arguments.
//
// Templates also don't officially have linkage, but since we ignore
// the C++ standard and look at template arguments when determining
// linkage and visibility of a template specialization, we might hit
// a template template argument that way. If we do, we need to
// consider its linkage.
if (!(isa<CXXMethodDecl>(D) ||
isa<VarDecl>(D) ||
isa<FieldDecl>(D) ||
isa<IndirectFieldDecl>(D) ||
isa<TagDecl>(D)))
isa<TagDecl>(D) ||
isa<TemplateDecl>(D)))
return LinkageInfo::none();
LinkageInfo LV;

View File

@ -220,3 +220,11 @@ namespace test17 {
}
template int *foo<42>();
}
// PR18408
namespace test18 {
template<template<typename> class> struct A {};
struct B { template<typename> struct C; };
void f(A<B::C>) {}
// CHECK-DAG: define void @_ZN6test181fENS_1AINS_1B1CEEE(
}