llvm-project/llvm/test/CodeGen/X86/regalloc-reconcile-broken-h...

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[RegAllocGreedy] Introduce a late pass to repair broken hints. A broken hint is a copy where both ends are assigned different colors. When a variable gets evicted in the neighborhood of such copies, it is likely we can reconcile some of them. ** Context ** Copies are inserted during the register allocation via splitting. These split points are required to relax the constraints on the allocation problem. When such a point is inserted, both ends of the copy would not share the same color with respect to the current allocation problem. When variables get evicted, the allocation problem becomes different and some split point may not be required anymore. However, the related variables may already have been colored. This usually shows up in the assembly with pattern like this: def A ... save A to B def A use A restore A from B ... use B Whereas we could simply have done: def B ... def A use A ... use B ** Proposed Solution ** A variable having a broken hint is marked for late recoloring if and only if selecting a register for it evict another variable. Indeed, if no eviction happens this is pointless to look for recoloring opportunities as it means the situation was the same as the initial allocation problem where we had to break the hint. Finally, when everything has been allocated, we look for recoloring opportunities for all the identified candidates. The recoloring is performed very late to rely on accurate copy cost (all involved variables are allocated). The recoloring is simple unlike the last change recoloring. It propagates the color of the broken hint to all its copy-related variables. If the color is available for them, the recoloring uses it, otherwise it gives up on that hint even if a more complex coloring would have worked. The recoloring happens only if it is profitable. The profitability is evaluated using the expected frequency of the copies of the currently recolored variable with a) its current color and b) with the target color. If a) is greater or equal than b), then it is profitable and the recoloring happen. ** Example ** Consider the following example: BB1: a = b = BB2: ... = b = a Let us assume b gets split: BB1: a = b = BB2: c = b ... d = c = d = a Because of how the allocation work, b, c, and d may be assigned different colors. Now, if a gets evicted to make room for c, assuming b and d were assigned to something different than a. We end up with: BB1: a = st a, SpillSlot b = BB2: c = b ... d = c = d e = ld SpillSlot = e This is likely that we can assign the same register for b, c, and d, getting rid of 2 copies. ** Performances ** Both ARM64 and x86_64 show performance improvements of up to 3% for the llvm-testsuite + externals with Os and O3. There are a few regressions too that comes from the (in)accuracy of the block frequency estimate. <rdar://problem/18312047> llvm-svn: 225422
2015-01-08 09:16:39 +08:00
; RUN: llc < %s -o - -mtriple=x86_64-apple-macosx | FileCheck %s
; Test case for the recoloring of broken hints.
; This is tricky to have something reasonably small to kick this optimization since
; it requires that spliting and spilling occur.
; The bottom line is that this test case is fragile.
; This was reduced from the make_list function from the llvm-testsuite:
; SingleSource/Benchmarks/McGill/chomp.c
target datalayout = "e-m:o-i64:64-f80:128-n8:16:32:64-S128"
target triple = "x86_64-apple-macosx10.9.0"
%struct._list = type { i32*, %struct._list* }
@ncol = external global i32, align 4
@nrow = external global i32, align 4
declare noalias i32* @copy_data()
declare noalias i8* @malloc(i64)
declare i32 @get_value()
declare i32 @in_wanted(i32* nocapture readonly)
declare noalias i32* @make_data()
; CHECK-LABEL: make_list:
; Function prologue.
; CHECK: pushq
; CHECK: subq ${{[0-9]+}}, %rsp
; Move the first argument (%data) into a temporary register.
; It will not survive the call to malloc otherwise.
; CHECK: movq %rdi, [[ARG1:%r[0-9a-z]+]]
; CHECK: callq _malloc
; Compute %data - 1 as used for load in land.rhs.i (via the variable %indvars.iv.next.i).
; CHECK: addq $-4, [[ARG1]]
; We use to produce a useless copy here and move %data in another temporary register.
; CHECK-NOT: movq [[ARG1]]
; End of the first basic block.
; CHECK: .align
; Now check that %data is used in an address computation.
; CHECK: leaq ([[ARG1]]
define %struct._list* @make_list(i32* nocapture readonly %data, i32* nocapture %value, i32* nocapture %all) {
entry:
%call = tail call i8* @malloc(i64 16)
[opaque pointer type] Add textual IR support for explicit type parameter to getelementptr instruction One of several parallel first steps to remove the target type of pointers, replacing them with a single opaque pointer type. This adds an explicit type parameter to the gep instruction so that when the first parameter becomes an opaque pointer type, the type to gep through is still available to the instructions. * This doesn't modify gep operators, only instructions (operators will be handled separately) * Textual IR changes only. Bitcode (including upgrade) and changing the in-memory representation will be in separate changes. * geps of vectors are transformed as: getelementptr <4 x float*> %x, ... ->getelementptr float, <4 x float*> %x, ... Then, once the opaque pointer type is introduced, this will ultimately look like: getelementptr float, <4 x ptr> %x with the unambiguous interpretation that it is a vector of pointers to float. * address spaces remain on the pointer, not the type: getelementptr float addrspace(1)* %x ->getelementptr float, float addrspace(1)* %x Then, eventually: getelementptr float, ptr addrspace(1) %x Importantly, the massive amount of test case churn has been automated by same crappy python code. I had to manually update a few test cases that wouldn't fit the script's model (r228970,r229196,r229197,r229198). The python script just massages stdin and writes the result to stdout, I then wrapped that in a shell script to handle replacing files, then using the usual find+xargs to migrate all the files. update.py: import fileinput import sys import re ibrep = re.compile(r"(^.*?[^%\w]getelementptr inbounds )(((?:<\d* x )?)(.*?)(| addrspace\(\d\)) *\*(|>)(?:$| *(?:%|@|null|undef|blockaddress|getelementptr|addrspacecast|bitcast|inttoptr|\[\[[a-zA-Z]|\{\{).*$))") normrep = re.compile( r"(^.*?[^%\w]getelementptr )(((?:<\d* x )?)(.*?)(| addrspace\(\d\)) *\*(|>)(?:$| *(?:%|@|null|undef|blockaddress|getelementptr|addrspacecast|bitcast|inttoptr|\[\[[a-zA-Z]|\{\{).*$))") def conv(match, line): if not match: return line line = match.groups()[0] if len(match.groups()[5]) == 0: line += match.groups()[2] line += match.groups()[3] line += ", " line += match.groups()[1] line += "\n" return line for line in sys.stdin: if line.find("getelementptr ") == line.find("getelementptr inbounds"): if line.find("getelementptr inbounds") != line.find("getelementptr inbounds ("): line = conv(re.match(ibrep, line), line) elif line.find("getelementptr ") != line.find("getelementptr ("): line = conv(re.match(normrep, line), line) sys.stdout.write(line) apply.sh: for name in "$@" do python3 `dirname "$0"`/update.py < "$name" > "$name.tmp" && mv "$name.tmp" "$name" rm -f "$name.tmp" done The actual commands: From llvm/src: find test/ -name *.ll | xargs ./apply.sh From llvm/src/tools/clang: find test/ -name *.mm -o -name *.m -o -name *.cpp -o -name *.c | xargs -I '{}' ../../apply.sh "{}" From llvm/src/tools/polly: find test/ -name *.ll | xargs ./apply.sh After that, check-all (with llvm, clang, clang-tools-extra, lld, compiler-rt, and polly all checked out). The extra 'rm' in the apply.sh script is due to a few files in clang's test suite using interesting unicode stuff that my python script was throwing exceptions on. None of those files needed to be migrated, so it seemed sufficient to ignore those cases. Reviewers: rafael, dexonsmith, grosser Differential Revision: http://reviews.llvm.org/D7636 llvm-svn: 230786
2015-02-28 03:29:02 +08:00
%next = getelementptr inbounds i8, i8* %call, i64 8
[RegAllocGreedy] Introduce a late pass to repair broken hints. A broken hint is a copy where both ends are assigned different colors. When a variable gets evicted in the neighborhood of such copies, it is likely we can reconcile some of them. ** Context ** Copies are inserted during the register allocation via splitting. These split points are required to relax the constraints on the allocation problem. When such a point is inserted, both ends of the copy would not share the same color with respect to the current allocation problem. When variables get evicted, the allocation problem becomes different and some split point may not be required anymore. However, the related variables may already have been colored. This usually shows up in the assembly with pattern like this: def A ... save A to B def A use A restore A from B ... use B Whereas we could simply have done: def B ... def A use A ... use B ** Proposed Solution ** A variable having a broken hint is marked for late recoloring if and only if selecting a register for it evict another variable. Indeed, if no eviction happens this is pointless to look for recoloring opportunities as it means the situation was the same as the initial allocation problem where we had to break the hint. Finally, when everything has been allocated, we look for recoloring opportunities for all the identified candidates. The recoloring is performed very late to rely on accurate copy cost (all involved variables are allocated). The recoloring is simple unlike the last change recoloring. It propagates the color of the broken hint to all its copy-related variables. If the color is available for them, the recoloring uses it, otherwise it gives up on that hint even if a more complex coloring would have worked. The recoloring happens only if it is profitable. The profitability is evaluated using the expected frequency of the copies of the currently recolored variable with a) its current color and b) with the target color. If a) is greater or equal than b), then it is profitable and the recoloring happen. ** Example ** Consider the following example: BB1: a = b = BB2: ... = b = a Let us assume b gets split: BB1: a = b = BB2: c = b ... d = c = d = a Because of how the allocation work, b, c, and d may be assigned different colors. Now, if a gets evicted to make room for c, assuming b and d were assigned to something different than a. We end up with: BB1: a = st a, SpillSlot b = BB2: c = b ... d = c = d e = ld SpillSlot = e This is likely that we can assign the same register for b, c, and d, getting rid of 2 copies. ** Performances ** Both ARM64 and x86_64 show performance improvements of up to 3% for the llvm-testsuite + externals with Os and O3. There are a few regressions too that comes from the (in)accuracy of the block frequency estimate. <rdar://problem/18312047> llvm-svn: 225422
2015-01-08 09:16:39 +08:00
%tmp = bitcast i8* %next to %struct._list**
%tmp2 = bitcast i8* %call to %struct._list*
%.pre78 = load i32, i32* @ncol, align 4
[RegAllocGreedy] Introduce a late pass to repair broken hints. A broken hint is a copy where both ends are assigned different colors. When a variable gets evicted in the neighborhood of such copies, it is likely we can reconcile some of them. ** Context ** Copies are inserted during the register allocation via splitting. These split points are required to relax the constraints on the allocation problem. When such a point is inserted, both ends of the copy would not share the same color with respect to the current allocation problem. When variables get evicted, the allocation problem becomes different and some split point may not be required anymore. However, the related variables may already have been colored. This usually shows up in the assembly with pattern like this: def A ... save A to B def A use A restore A from B ... use B Whereas we could simply have done: def B ... def A use A ... use B ** Proposed Solution ** A variable having a broken hint is marked for late recoloring if and only if selecting a register for it evict another variable. Indeed, if no eviction happens this is pointless to look for recoloring opportunities as it means the situation was the same as the initial allocation problem where we had to break the hint. Finally, when everything has been allocated, we look for recoloring opportunities for all the identified candidates. The recoloring is performed very late to rely on accurate copy cost (all involved variables are allocated). The recoloring is simple unlike the last change recoloring. It propagates the color of the broken hint to all its copy-related variables. If the color is available for them, the recoloring uses it, otherwise it gives up on that hint even if a more complex coloring would have worked. The recoloring happens only if it is profitable. The profitability is evaluated using the expected frequency of the copies of the currently recolored variable with a) its current color and b) with the target color. If a) is greater or equal than b), then it is profitable and the recoloring happen. ** Example ** Consider the following example: BB1: a = b = BB2: ... = b = a Let us assume b gets split: BB1: a = b = BB2: c = b ... d = c = d = a Because of how the allocation work, b, c, and d may be assigned different colors. Now, if a gets evicted to make room for c, assuming b and d were assigned to something different than a. We end up with: BB1: a = st a, SpillSlot b = BB2: c = b ... d = c = d e = ld SpillSlot = e This is likely that we can assign the same register for b, c, and d, getting rid of 2 copies. ** Performances ** Both ARM64 and x86_64 show performance improvements of up to 3% for the llvm-testsuite + externals with Os and O3. There are a few regressions too that comes from the (in)accuracy of the block frequency estimate. <rdar://problem/18312047> llvm-svn: 225422
2015-01-08 09:16:39 +08:00
br label %for.cond1.preheader
for.cond1.preheader: ; preds = %for.inc32, %entry
%tmp4 = phi i32 [ %.pre78, %entry ], [ 0, %for.inc32 ]
%current.077 = phi %struct._list* [ %tmp2, %entry ], [ %current.1.lcssa, %for.inc32 ]
%cmp270 = icmp eq i32 %tmp4, 0
br i1 %cmp270, label %for.inc32, label %for.body3
for.body3: ; preds = %if.end31, %for.cond1.preheader
%current.173 = phi %struct._list* [ %current.2, %if.end31 ], [ %current.077, %for.cond1.preheader ]
%row.172 = phi i32 [ %row.3, %if.end31 ], [ 0, %for.cond1.preheader ]
%col.071 = phi i32 [ %inc, %if.end31 ], [ 0, %for.cond1.preheader ]
%call4 = tail call i32* @make_data()
%tmp5 = load i32, i32* @ncol, align 4
[RegAllocGreedy] Introduce a late pass to repair broken hints. A broken hint is a copy where both ends are assigned different colors. When a variable gets evicted in the neighborhood of such copies, it is likely we can reconcile some of them. ** Context ** Copies are inserted during the register allocation via splitting. These split points are required to relax the constraints on the allocation problem. When such a point is inserted, both ends of the copy would not share the same color with respect to the current allocation problem. When variables get evicted, the allocation problem becomes different and some split point may not be required anymore. However, the related variables may already have been colored. This usually shows up in the assembly with pattern like this: def A ... save A to B def A use A restore A from B ... use B Whereas we could simply have done: def B ... def A use A ... use B ** Proposed Solution ** A variable having a broken hint is marked for late recoloring if and only if selecting a register for it evict another variable. Indeed, if no eviction happens this is pointless to look for recoloring opportunities as it means the situation was the same as the initial allocation problem where we had to break the hint. Finally, when everything has been allocated, we look for recoloring opportunities for all the identified candidates. The recoloring is performed very late to rely on accurate copy cost (all involved variables are allocated). The recoloring is simple unlike the last change recoloring. It propagates the color of the broken hint to all its copy-related variables. If the color is available for them, the recoloring uses it, otherwise it gives up on that hint even if a more complex coloring would have worked. The recoloring happens only if it is profitable. The profitability is evaluated using the expected frequency of the copies of the currently recolored variable with a) its current color and b) with the target color. If a) is greater or equal than b), then it is profitable and the recoloring happen. ** Example ** Consider the following example: BB1: a = b = BB2: ... = b = a Let us assume b gets split: BB1: a = b = BB2: c = b ... d = c = d = a Because of how the allocation work, b, c, and d may be assigned different colors. Now, if a gets evicted to make room for c, assuming b and d were assigned to something different than a. We end up with: BB1: a = st a, SpillSlot b = BB2: c = b ... d = c = d e = ld SpillSlot = e This is likely that we can assign the same register for b, c, and d, getting rid of 2 copies. ** Performances ** Both ARM64 and x86_64 show performance improvements of up to 3% for the llvm-testsuite + externals with Os and O3. There are a few regressions too that comes from the (in)accuracy of the block frequency estimate. <rdar://problem/18312047> llvm-svn: 225422
2015-01-08 09:16:39 +08:00
%tobool14.i = icmp eq i32 %tmp5, 0
br i1 %tobool14.i, label %while.cond.i, label %while.body.lr.ph.i
while.body.lr.ph.i: ; preds = %for.body3
%tmp6 = sext i32 %tmp5 to i64
br label %while.body.i
while.body.i: ; preds = %while.body.i, %while.body.lr.ph.i
%indvars.iv.i = phi i64 [ %tmp6, %while.body.lr.ph.i ], [ %indvars.iv.next.i, %while.body.i ]
%indvars.iv.next.i = add nsw i64 %indvars.iv.i, -1
%tmp9 = trunc i64 %indvars.iv.next.i to i32
%tobool.i = icmp eq i32 %tmp9, 0
br i1 %tobool.i, label %while.cond.i, label %while.body.i
while.cond.i: ; preds = %land.rhs.i, %while.body.i, %for.body3
%indvars.iv.i64 = phi i64 [ %indvars.iv.next.i65, %land.rhs.i ], [ 0, %for.body3 ], [ %tmp6, %while.body.i ]
%indvars.iv.next.i65 = add nsw i64 %indvars.iv.i64, -1
%tmp10 = trunc i64 %indvars.iv.i64 to i32
%tobool.i66 = icmp eq i32 %tmp10, 0
br i1 %tobool.i66, label %if.else, label %land.rhs.i
land.rhs.i: ; preds = %while.cond.i
[opaque pointer type] Add textual IR support for explicit type parameter to getelementptr instruction One of several parallel first steps to remove the target type of pointers, replacing them with a single opaque pointer type. This adds an explicit type parameter to the gep instruction so that when the first parameter becomes an opaque pointer type, the type to gep through is still available to the instructions. * This doesn't modify gep operators, only instructions (operators will be handled separately) * Textual IR changes only. Bitcode (including upgrade) and changing the in-memory representation will be in separate changes. * geps of vectors are transformed as: getelementptr <4 x float*> %x, ... ->getelementptr float, <4 x float*> %x, ... Then, once the opaque pointer type is introduced, this will ultimately look like: getelementptr float, <4 x ptr> %x with the unambiguous interpretation that it is a vector of pointers to float. * address spaces remain on the pointer, not the type: getelementptr float addrspace(1)* %x ->getelementptr float, float addrspace(1)* %x Then, eventually: getelementptr float, ptr addrspace(1) %x Importantly, the massive amount of test case churn has been automated by same crappy python code. I had to manually update a few test cases that wouldn't fit the script's model (r228970,r229196,r229197,r229198). The python script just massages stdin and writes the result to stdout, I then wrapped that in a shell script to handle replacing files, then using the usual find+xargs to migrate all the files. update.py: import fileinput import sys import re ibrep = re.compile(r"(^.*?[^%\w]getelementptr inbounds )(((?:<\d* x )?)(.*?)(| addrspace\(\d\)) *\*(|>)(?:$| *(?:%|@|null|undef|blockaddress|getelementptr|addrspacecast|bitcast|inttoptr|\[\[[a-zA-Z]|\{\{).*$))") normrep = re.compile( r"(^.*?[^%\w]getelementptr )(((?:<\d* x )?)(.*?)(| addrspace\(\d\)) *\*(|>)(?:$| *(?:%|@|null|undef|blockaddress|getelementptr|addrspacecast|bitcast|inttoptr|\[\[[a-zA-Z]|\{\{).*$))") def conv(match, line): if not match: return line line = match.groups()[0] if len(match.groups()[5]) == 0: line += match.groups()[2] line += match.groups()[3] line += ", " line += match.groups()[1] line += "\n" return line for line in sys.stdin: if line.find("getelementptr ") == line.find("getelementptr inbounds"): if line.find("getelementptr inbounds") != line.find("getelementptr inbounds ("): line = conv(re.match(ibrep, line), line) elif line.find("getelementptr ") != line.find("getelementptr ("): line = conv(re.match(normrep, line), line) sys.stdout.write(line) apply.sh: for name in "$@" do python3 `dirname "$0"`/update.py < "$name" > "$name.tmp" && mv "$name.tmp" "$name" rm -f "$name.tmp" done The actual commands: From llvm/src: find test/ -name *.ll | xargs ./apply.sh From llvm/src/tools/clang: find test/ -name *.mm -o -name *.m -o -name *.cpp -o -name *.c | xargs -I '{}' ../../apply.sh "{}" From llvm/src/tools/polly: find test/ -name *.ll | xargs ./apply.sh After that, check-all (with llvm, clang, clang-tools-extra, lld, compiler-rt, and polly all checked out). The extra 'rm' in the apply.sh script is due to a few files in clang's test suite using interesting unicode stuff that my python script was throwing exceptions on. None of those files needed to be migrated, so it seemed sufficient to ignore those cases. Reviewers: rafael, dexonsmith, grosser Differential Revision: http://reviews.llvm.org/D7636 llvm-svn: 230786
2015-02-28 03:29:02 +08:00
%arrayidx.i67 = getelementptr inbounds i32, i32* %call4, i64 %indvars.iv.next.i65
%tmp11 = load i32, i32* %arrayidx.i67, align 4
[opaque pointer type] Add textual IR support for explicit type parameter to getelementptr instruction One of several parallel first steps to remove the target type of pointers, replacing them with a single opaque pointer type. This adds an explicit type parameter to the gep instruction so that when the first parameter becomes an opaque pointer type, the type to gep through is still available to the instructions. * This doesn't modify gep operators, only instructions (operators will be handled separately) * Textual IR changes only. Bitcode (including upgrade) and changing the in-memory representation will be in separate changes. * geps of vectors are transformed as: getelementptr <4 x float*> %x, ... ->getelementptr float, <4 x float*> %x, ... Then, once the opaque pointer type is introduced, this will ultimately look like: getelementptr float, <4 x ptr> %x with the unambiguous interpretation that it is a vector of pointers to float. * address spaces remain on the pointer, not the type: getelementptr float addrspace(1)* %x ->getelementptr float, float addrspace(1)* %x Then, eventually: getelementptr float, ptr addrspace(1) %x Importantly, the massive amount of test case churn has been automated by same crappy python code. I had to manually update a few test cases that wouldn't fit the script's model (r228970,r229196,r229197,r229198). The python script just massages stdin and writes the result to stdout, I then wrapped that in a shell script to handle replacing files, then using the usual find+xargs to migrate all the files. update.py: import fileinput import sys import re ibrep = re.compile(r"(^.*?[^%\w]getelementptr inbounds )(((?:<\d* x )?)(.*?)(| addrspace\(\d\)) *\*(|>)(?:$| *(?:%|@|null|undef|blockaddress|getelementptr|addrspacecast|bitcast|inttoptr|\[\[[a-zA-Z]|\{\{).*$))") normrep = re.compile( r"(^.*?[^%\w]getelementptr )(((?:<\d* x )?)(.*?)(| addrspace\(\d\)) *\*(|>)(?:$| *(?:%|@|null|undef|blockaddress|getelementptr|addrspacecast|bitcast|inttoptr|\[\[[a-zA-Z]|\{\{).*$))") def conv(match, line): if not match: return line line = match.groups()[0] if len(match.groups()[5]) == 0: line += match.groups()[2] line += match.groups()[3] line += ", " line += match.groups()[1] line += "\n" return line for line in sys.stdin: if line.find("getelementptr ") == line.find("getelementptr inbounds"): if line.find("getelementptr inbounds") != line.find("getelementptr inbounds ("): line = conv(re.match(ibrep, line), line) elif line.find("getelementptr ") != line.find("getelementptr ("): line = conv(re.match(normrep, line), line) sys.stdout.write(line) apply.sh: for name in "$@" do python3 `dirname "$0"`/update.py < "$name" > "$name.tmp" && mv "$name.tmp" "$name" rm -f "$name.tmp" done The actual commands: From llvm/src: find test/ -name *.ll | xargs ./apply.sh From llvm/src/tools/clang: find test/ -name *.mm -o -name *.m -o -name *.cpp -o -name *.c | xargs -I '{}' ../../apply.sh "{}" From llvm/src/tools/polly: find test/ -name *.ll | xargs ./apply.sh After that, check-all (with llvm, clang, clang-tools-extra, lld, compiler-rt, and polly all checked out). The extra 'rm' in the apply.sh script is due to a few files in clang's test suite using interesting unicode stuff that my python script was throwing exceptions on. None of those files needed to be migrated, so it seemed sufficient to ignore those cases. Reviewers: rafael, dexonsmith, grosser Differential Revision: http://reviews.llvm.org/D7636 llvm-svn: 230786
2015-02-28 03:29:02 +08:00
%arrayidx2.i68 = getelementptr inbounds i32, i32* %data, i64 %indvars.iv.next.i65
%tmp12 = load i32, i32* %arrayidx2.i68, align 4
[RegAllocGreedy] Introduce a late pass to repair broken hints. A broken hint is a copy where both ends are assigned different colors. When a variable gets evicted in the neighborhood of such copies, it is likely we can reconcile some of them. ** Context ** Copies are inserted during the register allocation via splitting. These split points are required to relax the constraints on the allocation problem. When such a point is inserted, both ends of the copy would not share the same color with respect to the current allocation problem. When variables get evicted, the allocation problem becomes different and some split point may not be required anymore. However, the related variables may already have been colored. This usually shows up in the assembly with pattern like this: def A ... save A to B def A use A restore A from B ... use B Whereas we could simply have done: def B ... def A use A ... use B ** Proposed Solution ** A variable having a broken hint is marked for late recoloring if and only if selecting a register for it evict another variable. Indeed, if no eviction happens this is pointless to look for recoloring opportunities as it means the situation was the same as the initial allocation problem where we had to break the hint. Finally, when everything has been allocated, we look for recoloring opportunities for all the identified candidates. The recoloring is performed very late to rely on accurate copy cost (all involved variables are allocated). The recoloring is simple unlike the last change recoloring. It propagates the color of the broken hint to all its copy-related variables. If the color is available for them, the recoloring uses it, otherwise it gives up on that hint even if a more complex coloring would have worked. The recoloring happens only if it is profitable. The profitability is evaluated using the expected frequency of the copies of the currently recolored variable with a) its current color and b) with the target color. If a) is greater or equal than b), then it is profitable and the recoloring happen. ** Example ** Consider the following example: BB1: a = b = BB2: ... = b = a Let us assume b gets split: BB1: a = b = BB2: c = b ... d = c = d = a Because of how the allocation work, b, c, and d may be assigned different colors. Now, if a gets evicted to make room for c, assuming b and d were assigned to something different than a. We end up with: BB1: a = st a, SpillSlot b = BB2: c = b ... d = c = d e = ld SpillSlot = e This is likely that we can assign the same register for b, c, and d, getting rid of 2 copies. ** Performances ** Both ARM64 and x86_64 show performance improvements of up to 3% for the llvm-testsuite + externals with Os and O3. There are a few regressions too that comes from the (in)accuracy of the block frequency estimate. <rdar://problem/18312047> llvm-svn: 225422
2015-01-08 09:16:39 +08:00
%cmp.i69 = icmp eq i32 %tmp11, %tmp12
br i1 %cmp.i69, label %while.cond.i, label %equal_data.exit
equal_data.exit: ; preds = %land.rhs.i
%cmp3.i = icmp slt i32 %tmp10, 1
br i1 %cmp3.i, label %if.else, label %if.then
if.then: ; preds = %equal_data.exit
[opaque pointer type] Add textual IR support for explicit type parameter to getelementptr instruction One of several parallel first steps to remove the target type of pointers, replacing them with a single opaque pointer type. This adds an explicit type parameter to the gep instruction so that when the first parameter becomes an opaque pointer type, the type to gep through is still available to the instructions. * This doesn't modify gep operators, only instructions (operators will be handled separately) * Textual IR changes only. Bitcode (including upgrade) and changing the in-memory representation will be in separate changes. * geps of vectors are transformed as: getelementptr <4 x float*> %x, ... ->getelementptr float, <4 x float*> %x, ... Then, once the opaque pointer type is introduced, this will ultimately look like: getelementptr float, <4 x ptr> %x with the unambiguous interpretation that it is a vector of pointers to float. * address spaces remain on the pointer, not the type: getelementptr float addrspace(1)* %x ->getelementptr float, float addrspace(1)* %x Then, eventually: getelementptr float, ptr addrspace(1) %x Importantly, the massive amount of test case churn has been automated by same crappy python code. I had to manually update a few test cases that wouldn't fit the script's model (r228970,r229196,r229197,r229198). The python script just massages stdin and writes the result to stdout, I then wrapped that in a shell script to handle replacing files, then using the usual find+xargs to migrate all the files. update.py: import fileinput import sys import re ibrep = re.compile(r"(^.*?[^%\w]getelementptr inbounds )(((?:<\d* x )?)(.*?)(| addrspace\(\d\)) *\*(|>)(?:$| *(?:%|@|null|undef|blockaddress|getelementptr|addrspacecast|bitcast|inttoptr|\[\[[a-zA-Z]|\{\{).*$))") normrep = re.compile( r"(^.*?[^%\w]getelementptr )(((?:<\d* x )?)(.*?)(| addrspace\(\d\)) *\*(|>)(?:$| *(?:%|@|null|undef|blockaddress|getelementptr|addrspacecast|bitcast|inttoptr|\[\[[a-zA-Z]|\{\{).*$))") def conv(match, line): if not match: return line line = match.groups()[0] if len(match.groups()[5]) == 0: line += match.groups()[2] line += match.groups()[3] line += ", " line += match.groups()[1] line += "\n" return line for line in sys.stdin: if line.find("getelementptr ") == line.find("getelementptr inbounds"): if line.find("getelementptr inbounds") != line.find("getelementptr inbounds ("): line = conv(re.match(ibrep, line), line) elif line.find("getelementptr ") != line.find("getelementptr ("): line = conv(re.match(normrep, line), line) sys.stdout.write(line) apply.sh: for name in "$@" do python3 `dirname "$0"`/update.py < "$name" > "$name.tmp" && mv "$name.tmp" "$name" rm -f "$name.tmp" done The actual commands: From llvm/src: find test/ -name *.ll | xargs ./apply.sh From llvm/src/tools/clang: find test/ -name *.mm -o -name *.m -o -name *.cpp -o -name *.c | xargs -I '{}' ../../apply.sh "{}" From llvm/src/tools/polly: find test/ -name *.ll | xargs ./apply.sh After that, check-all (with llvm, clang, clang-tools-extra, lld, compiler-rt, and polly all checked out). The extra 'rm' in the apply.sh script is due to a few files in clang's test suite using interesting unicode stuff that my python script was throwing exceptions on. None of those files needed to be migrated, so it seemed sufficient to ignore those cases. Reviewers: rafael, dexonsmith, grosser Differential Revision: http://reviews.llvm.org/D7636 llvm-svn: 230786
2015-02-28 03:29:02 +08:00
%next7 = getelementptr inbounds %struct._list, %struct._list* %current.173, i64 0, i32 1
%tmp14 = load %struct._list*, %struct._list** %next7, align 8
[opaque pointer type] Add textual IR support for explicit type parameter to getelementptr instruction One of several parallel first steps to remove the target type of pointers, replacing them with a single opaque pointer type. This adds an explicit type parameter to the gep instruction so that when the first parameter becomes an opaque pointer type, the type to gep through is still available to the instructions. * This doesn't modify gep operators, only instructions (operators will be handled separately) * Textual IR changes only. Bitcode (including upgrade) and changing the in-memory representation will be in separate changes. * geps of vectors are transformed as: getelementptr <4 x float*> %x, ... ->getelementptr float, <4 x float*> %x, ... Then, once the opaque pointer type is introduced, this will ultimately look like: getelementptr float, <4 x ptr> %x with the unambiguous interpretation that it is a vector of pointers to float. * address spaces remain on the pointer, not the type: getelementptr float addrspace(1)* %x ->getelementptr float, float addrspace(1)* %x Then, eventually: getelementptr float, ptr addrspace(1) %x Importantly, the massive amount of test case churn has been automated by same crappy python code. I had to manually update a few test cases that wouldn't fit the script's model (r228970,r229196,r229197,r229198). The python script just massages stdin and writes the result to stdout, I then wrapped that in a shell script to handle replacing files, then using the usual find+xargs to migrate all the files. update.py: import fileinput import sys import re ibrep = re.compile(r"(^.*?[^%\w]getelementptr inbounds )(((?:<\d* x )?)(.*?)(| addrspace\(\d\)) *\*(|>)(?:$| *(?:%|@|null|undef|blockaddress|getelementptr|addrspacecast|bitcast|inttoptr|\[\[[a-zA-Z]|\{\{).*$))") normrep = re.compile( r"(^.*?[^%\w]getelementptr )(((?:<\d* x )?)(.*?)(| addrspace\(\d\)) *\*(|>)(?:$| *(?:%|@|null|undef|blockaddress|getelementptr|addrspacecast|bitcast|inttoptr|\[\[[a-zA-Z]|\{\{).*$))") def conv(match, line): if not match: return line line = match.groups()[0] if len(match.groups()[5]) == 0: line += match.groups()[2] line += match.groups()[3] line += ", " line += match.groups()[1] line += "\n" return line for line in sys.stdin: if line.find("getelementptr ") == line.find("getelementptr inbounds"): if line.find("getelementptr inbounds") != line.find("getelementptr inbounds ("): line = conv(re.match(ibrep, line), line) elif line.find("getelementptr ") != line.find("getelementptr ("): line = conv(re.match(normrep, line), line) sys.stdout.write(line) apply.sh: for name in "$@" do python3 `dirname "$0"`/update.py < "$name" > "$name.tmp" && mv "$name.tmp" "$name" rm -f "$name.tmp" done The actual commands: From llvm/src: find test/ -name *.ll | xargs ./apply.sh From llvm/src/tools/clang: find test/ -name *.mm -o -name *.m -o -name *.cpp -o -name *.c | xargs -I '{}' ../../apply.sh "{}" From llvm/src/tools/polly: find test/ -name *.ll | xargs ./apply.sh After that, check-all (with llvm, clang, clang-tools-extra, lld, compiler-rt, and polly all checked out). The extra 'rm' in the apply.sh script is due to a few files in clang's test suite using interesting unicode stuff that my python script was throwing exceptions on. None of those files needed to be migrated, so it seemed sufficient to ignore those cases. Reviewers: rafael, dexonsmith, grosser Differential Revision: http://reviews.llvm.org/D7636 llvm-svn: 230786
2015-02-28 03:29:02 +08:00
%next12 = getelementptr inbounds %struct._list, %struct._list* %tmp14, i64 0, i32 1
[RegAllocGreedy] Introduce a late pass to repair broken hints. A broken hint is a copy where both ends are assigned different colors. When a variable gets evicted in the neighborhood of such copies, it is likely we can reconcile some of them. ** Context ** Copies are inserted during the register allocation via splitting. These split points are required to relax the constraints on the allocation problem. When such a point is inserted, both ends of the copy would not share the same color with respect to the current allocation problem. When variables get evicted, the allocation problem becomes different and some split point may not be required anymore. However, the related variables may already have been colored. This usually shows up in the assembly with pattern like this: def A ... save A to B def A use A restore A from B ... use B Whereas we could simply have done: def B ... def A use A ... use B ** Proposed Solution ** A variable having a broken hint is marked for late recoloring if and only if selecting a register for it evict another variable. Indeed, if no eviction happens this is pointless to look for recoloring opportunities as it means the situation was the same as the initial allocation problem where we had to break the hint. Finally, when everything has been allocated, we look for recoloring opportunities for all the identified candidates. The recoloring is performed very late to rely on accurate copy cost (all involved variables are allocated). The recoloring is simple unlike the last change recoloring. It propagates the color of the broken hint to all its copy-related variables. If the color is available for them, the recoloring uses it, otherwise it gives up on that hint even if a more complex coloring would have worked. The recoloring happens only if it is profitable. The profitability is evaluated using the expected frequency of the copies of the currently recolored variable with a) its current color and b) with the target color. If a) is greater or equal than b), then it is profitable and the recoloring happen. ** Example ** Consider the following example: BB1: a = b = BB2: ... = b = a Let us assume b gets split: BB1: a = b = BB2: c = b ... d = c = d = a Because of how the allocation work, b, c, and d may be assigned different colors. Now, if a gets evicted to make room for c, assuming b and d were assigned to something different than a. We end up with: BB1: a = st a, SpillSlot b = BB2: c = b ... d = c = d e = ld SpillSlot = e This is likely that we can assign the same register for b, c, and d, getting rid of 2 copies. ** Performances ** Both ARM64 and x86_64 show performance improvements of up to 3% for the llvm-testsuite + externals with Os and O3. There are a few regressions too that comes from the (in)accuracy of the block frequency estimate. <rdar://problem/18312047> llvm-svn: 225422
2015-01-08 09:16:39 +08:00
store %struct._list* null, %struct._list** %next12, align 8
%tmp15 = load %struct._list*, %struct._list** %next7, align 8
%tmp16 = load i32, i32* %value, align 4
[RegAllocGreedy] Introduce a late pass to repair broken hints. A broken hint is a copy where both ends are assigned different colors. When a variable gets evicted in the neighborhood of such copies, it is likely we can reconcile some of them. ** Context ** Copies are inserted during the register allocation via splitting. These split points are required to relax the constraints on the allocation problem. When such a point is inserted, both ends of the copy would not share the same color with respect to the current allocation problem. When variables get evicted, the allocation problem becomes different and some split point may not be required anymore. However, the related variables may already have been colored. This usually shows up in the assembly with pattern like this: def A ... save A to B def A use A restore A from B ... use B Whereas we could simply have done: def B ... def A use A ... use B ** Proposed Solution ** A variable having a broken hint is marked for late recoloring if and only if selecting a register for it evict another variable. Indeed, if no eviction happens this is pointless to look for recoloring opportunities as it means the situation was the same as the initial allocation problem where we had to break the hint. Finally, when everything has been allocated, we look for recoloring opportunities for all the identified candidates. The recoloring is performed very late to rely on accurate copy cost (all involved variables are allocated). The recoloring is simple unlike the last change recoloring. It propagates the color of the broken hint to all its copy-related variables. If the color is available for them, the recoloring uses it, otherwise it gives up on that hint even if a more complex coloring would have worked. The recoloring happens only if it is profitable. The profitability is evaluated using the expected frequency of the copies of the currently recolored variable with a) its current color and b) with the target color. If a) is greater or equal than b), then it is profitable and the recoloring happen. ** Example ** Consider the following example: BB1: a = b = BB2: ... = b = a Let us assume b gets split: BB1: a = b = BB2: c = b ... d = c = d = a Because of how the allocation work, b, c, and d may be assigned different colors. Now, if a gets evicted to make room for c, assuming b and d were assigned to something different than a. We end up with: BB1: a = st a, SpillSlot b = BB2: c = b ... d = c = d e = ld SpillSlot = e This is likely that we can assign the same register for b, c, and d, getting rid of 2 copies. ** Performances ** Both ARM64 and x86_64 show performance improvements of up to 3% for the llvm-testsuite + externals with Os and O3. There are a few regressions too that comes from the (in)accuracy of the block frequency estimate. <rdar://problem/18312047> llvm-svn: 225422
2015-01-08 09:16:39 +08:00
%cmp14 = icmp eq i32 %tmp16, 1
%.tmp16 = select i1 %cmp14, i32 0, i32 %tmp16
%tmp18 = load i32, i32* %all, align 4
[RegAllocGreedy] Introduce a late pass to repair broken hints. A broken hint is a copy where both ends are assigned different colors. When a variable gets evicted in the neighborhood of such copies, it is likely we can reconcile some of them. ** Context ** Copies are inserted during the register allocation via splitting. These split points are required to relax the constraints on the allocation problem. When such a point is inserted, both ends of the copy would not share the same color with respect to the current allocation problem. When variables get evicted, the allocation problem becomes different and some split point may not be required anymore. However, the related variables may already have been colored. This usually shows up in the assembly with pattern like this: def A ... save A to B def A use A restore A from B ... use B Whereas we could simply have done: def B ... def A use A ... use B ** Proposed Solution ** A variable having a broken hint is marked for late recoloring if and only if selecting a register for it evict another variable. Indeed, if no eviction happens this is pointless to look for recoloring opportunities as it means the situation was the same as the initial allocation problem where we had to break the hint. Finally, when everything has been allocated, we look for recoloring opportunities for all the identified candidates. The recoloring is performed very late to rely on accurate copy cost (all involved variables are allocated). The recoloring is simple unlike the last change recoloring. It propagates the color of the broken hint to all its copy-related variables. If the color is available for them, the recoloring uses it, otherwise it gives up on that hint even if a more complex coloring would have worked. The recoloring happens only if it is profitable. The profitability is evaluated using the expected frequency of the copies of the currently recolored variable with a) its current color and b) with the target color. If a) is greater or equal than b), then it is profitable and the recoloring happen. ** Example ** Consider the following example: BB1: a = b = BB2: ... = b = a Let us assume b gets split: BB1: a = b = BB2: c = b ... d = c = d = a Because of how the allocation work, b, c, and d may be assigned different colors. Now, if a gets evicted to make room for c, assuming b and d were assigned to something different than a. We end up with: BB1: a = st a, SpillSlot b = BB2: c = b ... d = c = d e = ld SpillSlot = e This is likely that we can assign the same register for b, c, and d, getting rid of 2 copies. ** Performances ** Both ARM64 and x86_64 show performance improvements of up to 3% for the llvm-testsuite + externals with Os and O3. There are a few regressions too that comes from the (in)accuracy of the block frequency estimate. <rdar://problem/18312047> llvm-svn: 225422
2015-01-08 09:16:39 +08:00
%tmp19 = or i32 %tmp18, %.tmp16
%tmp20 = icmp eq i32 %tmp19, 0
br i1 %tmp20, label %if.then19, label %if.end31
if.then19: ; preds = %if.then
%call21 = tail call i32 @in_wanted(i32* %call4)
br label %if.end31
if.else: ; preds = %equal_data.exit, %while.cond.i
%cmp26 = icmp eq i32 %col.071, 0
%.row.172 = select i1 %cmp26, i32 0, i32 %row.172
%sub30 = add nsw i32 %tmp5, -1
br label %if.end31
if.end31: ; preds = %if.else, %if.then19, %if.then
%col.1 = phi i32 [ %sub30, %if.else ], [ 0, %if.then ], [ 0, %if.then19 ]
%row.3 = phi i32 [ %.row.172, %if.else ], [ %row.172, %if.then ], [ 0, %if.then19 ]
%current.2 = phi %struct._list* [ %current.173, %if.else ], [ %tmp15, %if.then ], [ %tmp15, %if.then19 ]
%inc = add nsw i32 %col.1, 1
%tmp25 = load i32, i32* @ncol, align 4
[RegAllocGreedy] Introduce a late pass to repair broken hints. A broken hint is a copy where both ends are assigned different colors. When a variable gets evicted in the neighborhood of such copies, it is likely we can reconcile some of them. ** Context ** Copies are inserted during the register allocation via splitting. These split points are required to relax the constraints on the allocation problem. When such a point is inserted, both ends of the copy would not share the same color with respect to the current allocation problem. When variables get evicted, the allocation problem becomes different and some split point may not be required anymore. However, the related variables may already have been colored. This usually shows up in the assembly with pattern like this: def A ... save A to B def A use A restore A from B ... use B Whereas we could simply have done: def B ... def A use A ... use B ** Proposed Solution ** A variable having a broken hint is marked for late recoloring if and only if selecting a register for it evict another variable. Indeed, if no eviction happens this is pointless to look for recoloring opportunities as it means the situation was the same as the initial allocation problem where we had to break the hint. Finally, when everything has been allocated, we look for recoloring opportunities for all the identified candidates. The recoloring is performed very late to rely on accurate copy cost (all involved variables are allocated). The recoloring is simple unlike the last change recoloring. It propagates the color of the broken hint to all its copy-related variables. If the color is available for them, the recoloring uses it, otherwise it gives up on that hint even if a more complex coloring would have worked. The recoloring happens only if it is profitable. The profitability is evaluated using the expected frequency of the copies of the currently recolored variable with a) its current color and b) with the target color. If a) is greater or equal than b), then it is profitable and the recoloring happen. ** Example ** Consider the following example: BB1: a = b = BB2: ... = b = a Let us assume b gets split: BB1: a = b = BB2: c = b ... d = c = d = a Because of how the allocation work, b, c, and d may be assigned different colors. Now, if a gets evicted to make room for c, assuming b and d were assigned to something different than a. We end up with: BB1: a = st a, SpillSlot b = BB2: c = b ... d = c = d e = ld SpillSlot = e This is likely that we can assign the same register for b, c, and d, getting rid of 2 copies. ** Performances ** Both ARM64 and x86_64 show performance improvements of up to 3% for the llvm-testsuite + externals with Os and O3. There are a few regressions too that comes from the (in)accuracy of the block frequency estimate. <rdar://problem/18312047> llvm-svn: 225422
2015-01-08 09:16:39 +08:00
%cmp2 = icmp eq i32 %inc, %tmp25
br i1 %cmp2, label %for.cond1.for.inc32_crit_edge, label %for.body3
for.cond1.for.inc32_crit_edge: ; preds = %if.end31
%.pre79 = load i32, i32* @nrow, align 4
[RegAllocGreedy] Introduce a late pass to repair broken hints. A broken hint is a copy where both ends are assigned different colors. When a variable gets evicted in the neighborhood of such copies, it is likely we can reconcile some of them. ** Context ** Copies are inserted during the register allocation via splitting. These split points are required to relax the constraints on the allocation problem. When such a point is inserted, both ends of the copy would not share the same color with respect to the current allocation problem. When variables get evicted, the allocation problem becomes different and some split point may not be required anymore. However, the related variables may already have been colored. This usually shows up in the assembly with pattern like this: def A ... save A to B def A use A restore A from B ... use B Whereas we could simply have done: def B ... def A use A ... use B ** Proposed Solution ** A variable having a broken hint is marked for late recoloring if and only if selecting a register for it evict another variable. Indeed, if no eviction happens this is pointless to look for recoloring opportunities as it means the situation was the same as the initial allocation problem where we had to break the hint. Finally, when everything has been allocated, we look for recoloring opportunities for all the identified candidates. The recoloring is performed very late to rely on accurate copy cost (all involved variables are allocated). The recoloring is simple unlike the last change recoloring. It propagates the color of the broken hint to all its copy-related variables. If the color is available for them, the recoloring uses it, otherwise it gives up on that hint even if a more complex coloring would have worked. The recoloring happens only if it is profitable. The profitability is evaluated using the expected frequency of the copies of the currently recolored variable with a) its current color and b) with the target color. If a) is greater or equal than b), then it is profitable and the recoloring happen. ** Example ** Consider the following example: BB1: a = b = BB2: ... = b = a Let us assume b gets split: BB1: a = b = BB2: c = b ... d = c = d = a Because of how the allocation work, b, c, and d may be assigned different colors. Now, if a gets evicted to make room for c, assuming b and d were assigned to something different than a. We end up with: BB1: a = st a, SpillSlot b = BB2: c = b ... d = c = d e = ld SpillSlot = e This is likely that we can assign the same register for b, c, and d, getting rid of 2 copies. ** Performances ** Both ARM64 and x86_64 show performance improvements of up to 3% for the llvm-testsuite + externals with Os and O3. There are a few regressions too that comes from the (in)accuracy of the block frequency estimate. <rdar://problem/18312047> llvm-svn: 225422
2015-01-08 09:16:39 +08:00
br label %for.inc32
for.inc32: ; preds = %for.cond1.for.inc32_crit_edge, %for.cond1.preheader
%tmp26 = phi i32 [ %.pre79, %for.cond1.for.inc32_crit_edge ], [ 0, %for.cond1.preheader ]
%current.1.lcssa = phi %struct._list* [ %current.2, %for.cond1.for.inc32_crit_edge ], [ %current.077, %for.cond1.preheader ]
%row.1.lcssa = phi i32 [ %row.3, %for.cond1.for.inc32_crit_edge ], [ 0, %for.cond1.preheader ]
%inc33 = add nsw i32 %row.1.lcssa, 1
%cmp = icmp eq i32 %inc33, %tmp26
br i1 %cmp, label %for.end34, label %for.cond1.preheader
for.end34: ; preds = %for.inc32
%.pre = load %struct._list*, %struct._list** %tmp, align 8
[RegAllocGreedy] Introduce a late pass to repair broken hints. A broken hint is a copy where both ends are assigned different colors. When a variable gets evicted in the neighborhood of such copies, it is likely we can reconcile some of them. ** Context ** Copies are inserted during the register allocation via splitting. These split points are required to relax the constraints on the allocation problem. When such a point is inserted, both ends of the copy would not share the same color with respect to the current allocation problem. When variables get evicted, the allocation problem becomes different and some split point may not be required anymore. However, the related variables may already have been colored. This usually shows up in the assembly with pattern like this: def A ... save A to B def A use A restore A from B ... use B Whereas we could simply have done: def B ... def A use A ... use B ** Proposed Solution ** A variable having a broken hint is marked for late recoloring if and only if selecting a register for it evict another variable. Indeed, if no eviction happens this is pointless to look for recoloring opportunities as it means the situation was the same as the initial allocation problem where we had to break the hint. Finally, when everything has been allocated, we look for recoloring opportunities for all the identified candidates. The recoloring is performed very late to rely on accurate copy cost (all involved variables are allocated). The recoloring is simple unlike the last change recoloring. It propagates the color of the broken hint to all its copy-related variables. If the color is available for them, the recoloring uses it, otherwise it gives up on that hint even if a more complex coloring would have worked. The recoloring happens only if it is profitable. The profitability is evaluated using the expected frequency of the copies of the currently recolored variable with a) its current color and b) with the target color. If a) is greater or equal than b), then it is profitable and the recoloring happen. ** Example ** Consider the following example: BB1: a = b = BB2: ... = b = a Let us assume b gets split: BB1: a = b = BB2: c = b ... d = c = d = a Because of how the allocation work, b, c, and d may be assigned different colors. Now, if a gets evicted to make room for c, assuming b and d were assigned to something different than a. We end up with: BB1: a = st a, SpillSlot b = BB2: c = b ... d = c = d e = ld SpillSlot = e This is likely that we can assign the same register for b, c, and d, getting rid of 2 copies. ** Performances ** Both ARM64 and x86_64 show performance improvements of up to 3% for the llvm-testsuite + externals with Os and O3. There are a few regressions too that comes from the (in)accuracy of the block frequency estimate. <rdar://problem/18312047> llvm-svn: 225422
2015-01-08 09:16:39 +08:00
ret %struct._list* %.pre
}