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@ -83,12 +83,12 @@ pressure-volume. It would need to be divided by a per-atom volume to
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have units of stress (pressure), but an individual atom's volume is
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not easy to compute in a deformed solid or a liquid. Thus, if the
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diagonal components of the per-atom stress tensor are summed for all
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atoms in the system and the sum is divided by 3V, where V is the
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volume of the system, the result should be -P, where P is the total
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pressure of the system.
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atoms in the system and the sum is divided by dV, where d = dimension
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and V is the volume of the system, the result should be -P, where P is
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the total pressure of the system.
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</P>
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<P>These lines in an input script should yield that result. I.e. the
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last 2 columns of thermo output will be the same:
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<P>These lines in an input script for a 3d system should yield that
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result. I.e. the last 2 columns of thermo output will be the same:
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</P>
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<PRE>compute peratom all stress/atom
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compute p all reduce sum c_peratom[1] c_peratom[2] c_peratom[3]
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@ -80,12 +80,12 @@ pressure-volume. It would need to be divided by a per-atom volume to
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have units of stress (pressure), but an individual atom's volume is
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not easy to compute in a deformed solid or a liquid. Thus, if the
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diagonal components of the per-atom stress tensor are summed for all
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atoms in the system and the sum is divided by 3V, where V is the
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volume of the system, the result should be -P, where P is the total
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pressure of the system.
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atoms in the system and the sum is divided by dV, where d = dimension
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and V is the volume of the system, the result should be -P, where P is
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the total pressure of the system.
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These lines in an input script should yield that result. I.e. the
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last 2 columns of thermo output will be the same:
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These lines in an input script for a 3d system should yield that
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result. I.e. the last 2 columns of thermo output will be the same:
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compute peratom all stress/atom
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compute p all reduce sum c_peratom\[1\] c_peratom\[2\] c_peratom\[3\]
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