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@ -79,11 +79,11 @@ of the per-atom pressure tensor. It is also really a stress-volume
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formulation, meaning the computed quantity is in units of
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pressure-volume. It would need to be divided by a per-atom volume to
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have units of stress (pressure), but an individual atom's volume is
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not easy to compute in a deformed solid or a liquid. Thus, if the
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diagonal components of the per-atom stress tensor are summed for all
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atoms in the system and the sum is divided by dV, where d = dimension
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and V is the volume of the system, the result should be -P, where P is
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the total pressure of the system.
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not well defined or easy to compute in a deformed solid or a liquid.
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Thus, if the diagonal components of the per-atom stress tensor are
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summed for all atoms in the system and the sum is divided by dV, where
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d = dimension and V is the volume of the system, the result should be
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-P, where P is the total pressure of the system.
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</P>
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<P>These lines in an input script for a 3d system should yield that
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result. I.e. the last 2 columns of thermo output will be the same:
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@ -105,8 +105,8 @@ accessed by indices 1-6 by any command that uses per-atom values from
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a compute as input. See <A HREF = "Section_howto.html#4_15">this section</A> for an
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overview of LAMMPS output options.
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</P>
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<P>The per-atom array values will be in whatever <A HREF = "units.html">units</A> the
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quantities being reduced are in.
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<P>The per-atom array values will be in pressure*volume
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<A HREF = "units.html">units</A> as discussed above.
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</P>
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<P><B>Restrictions:</B> none
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</P>
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@ -76,11 +76,11 @@ of the per-atom pressure tensor. It is also really a stress-volume
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formulation, meaning the computed quantity is in units of
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pressure-volume. It would need to be divided by a per-atom volume to
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have units of stress (pressure), but an individual atom's volume is
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not easy to compute in a deformed solid or a liquid. Thus, if the
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diagonal components of the per-atom stress tensor are summed for all
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atoms in the system and the sum is divided by dV, where d = dimension
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and V is the volume of the system, the result should be -P, where P is
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the total pressure of the system.
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not well defined or easy to compute in a deformed solid or a liquid.
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Thus, if the diagonal components of the per-atom stress tensor are
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summed for all atoms in the system and the sum is divided by dV, where
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d = dimension and V is the volume of the system, the result should be
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-P, where P is the total pressure of the system.
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These lines in an input script for a 3d system should yield that
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result. I.e. the last 2 columns of thermo output will be the same:
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@ -102,8 +102,8 @@ accessed by indices 1-6 by any command that uses per-atom values from
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a compute as input. See "this section"_Section_howto.html#4_15 for an
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overview of LAMMPS output options.
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The per-atom array values will be in whatever "units"_units.html the
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quantities being reduced are in.
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The per-atom array values will be in pressure*volume
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"units"_units.html as discussed above.
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[Restrictions:] none
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