signal: make sig_handler_ignored() return bool
sig_handler_ignored() already behaves like a boolean function. Let's actually declare it as such too. Link: http://lkml.kernel.org/r/20180602103653.18181-8-christian@brauner.io Signed-off-by: Christian Brauner <christian@brauner.io> Reviewed-by: Andrew Morton <akpm@linux-foundation.org> Cc: Al Viro <viro@zeniv.linux.org.uk> Cc: Eric W. Biederman <ebiederm@xmission.com> Cc: Greg Kroah-Hartman <gregkh@linuxfoundation.org> Cc: Ingo Molnar <mingo@kernel.org> Cc: James Morris <james.morris@microsoft.com> Cc: Kees Cook <keescook@chromium.org> Cc: Oleg Nesterov <oleg@redhat.com> Cc: Peter Zijlstra <peterz@infradead.org> Cc: Stephen Smalley <sds@tycho.nsa.gov> Signed-off-by: Andrew Morton <akpm@linux-foundation.org> Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
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@ -65,11 +65,11 @@ static void __user *sig_handler(struct task_struct *t, int sig)
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return t->sighand->action[sig - 1].sa.sa_handler;
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}
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static int sig_handler_ignored(void __user *handler, int sig)
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static inline bool sig_handler_ignored(void __user *handler, int sig)
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{
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/* Is it explicitly or implicitly ignored? */
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return handler == SIG_IGN ||
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(handler == SIG_DFL && sig_kernel_ignore(sig));
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(handler == SIG_DFL && sig_kernel_ignore(sig));
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}
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static int sig_task_ignored(struct task_struct *t, int sig, bool force)
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