sched: Make finish_task_switch() return 'struct rq *'
Both callers of finish_task_switch() need to recalculate this_rq() and pass it as an argument, plus __schedule() does this again after context_switch(). It would be simpler to call this_rq() once in finish_task_switch() and return the this rq to the callers. Note: probably "int cpu" in __schedule() should die; it is not used and both rcu_note_context_switch() and wq_worker_sleeping() do not really need this argument. Signed-off-by: Oleg Nesterov <oleg@redhat.com> Signed-off-by: Peter Zijlstra (Intel) <peterz@infradead.org> Cc: Kirill Tkhai <tkhai@yandex.ru> Cc: Steven Rostedt <rostedt@goodmis.org> Cc: Linus Torvalds <torvalds@linux-foundation.org> Link: http://lkml.kernel.org/r/20141009193232.GB5408@redhat.com Signed-off-by: Ingo Molnar <mingo@kernel.org>
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@ -2220,7 +2220,6 @@ prepare_task_switch(struct rq *rq, struct task_struct *prev,
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/**
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* finish_task_switch - clean up after a task-switch
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* @rq: runqueue associated with task-switch
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* @prev: the thread we just switched away from.
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*
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* finish_task_switch must be called after the context switch, paired
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@ -2232,10 +2231,16 @@ prepare_task_switch(struct rq *rq, struct task_struct *prev,
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* so, we finish that here outside of the runqueue lock. (Doing it
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* with the lock held can cause deadlocks; see schedule() for
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* details.)
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*
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* The context switch have flipped the stack from under us and restored the
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* local variables which were saved when this task called schedule() in the
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* past. prev == current is still correct but we need to recalculate this_rq
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* because prev may have moved to another CPU.
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*/
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static void finish_task_switch(struct rq *rq, struct task_struct *prev)
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static struct rq *finish_task_switch(struct task_struct *prev)
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__releases(rq->lock)
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{
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struct rq *rq = this_rq();
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struct mm_struct *mm = rq->prev_mm;
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long prev_state;
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@ -2275,6 +2280,7 @@ static void finish_task_switch(struct rq *rq, struct task_struct *prev)
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}
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tick_nohz_task_switch(current);
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return rq;
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}
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#ifdef CONFIG_SMP
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@ -2313,8 +2319,7 @@ asmlinkage __visible void schedule_tail(struct task_struct *prev)
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/* finish_task_switch() drops rq->lock and enables preemtion */
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preempt_disable();
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rq = this_rq();
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finish_task_switch(rq, prev);
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rq = finish_task_switch(prev);
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post_schedule(rq);
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preempt_enable();
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@ -2323,10 +2328,9 @@ asmlinkage __visible void schedule_tail(struct task_struct *prev)
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}
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/*
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* context_switch - switch to the new MM and the new
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* thread's register state.
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* context_switch - switch to the new MM and the new thread's register state.
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*/
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static inline void
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static inline struct rq *
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context_switch(struct rq *rq, struct task_struct *prev,
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struct task_struct *next)
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{
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@ -2365,14 +2369,9 @@ context_switch(struct rq *rq, struct task_struct *prev,
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context_tracking_task_switch(prev, next);
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/* Here we just switch the register state and the stack. */
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switch_to(prev, next, prev);
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barrier();
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/*
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* this_rq must be evaluated again because prev may have moved
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* CPUs since it called schedule(), thus the 'rq' on its stack
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* frame will be invalid.
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*/
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finish_task_switch(this_rq(), prev);
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return finish_task_switch(prev);
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}
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/*
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@ -2854,15 +2853,8 @@ need_resched:
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rq->curr = next;
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++*switch_count;
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context_switch(rq, prev, next); /* unlocks the rq */
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/*
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* The context switch have flipped the stack from under us
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* and restored the local variables which were saved when
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* this task called schedule() in the past. prev == current
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* is still correct, but it can be moved to another cpu/rq.
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*/
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cpu = smp_processor_id();
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rq = cpu_rq(cpu);
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rq = context_switch(rq, prev, next); /* unlocks the rq */
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cpu = cpu_of(rq);
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} else
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raw_spin_unlock_irq(&rq->lock);
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