btrfs: volumes: Remove the meaningless condition of minimal nr_devs when allocating a chunk
When checking the minimal nr_devs, there is one dead and meaningless condition: if (ndevs < devs_increment * sub_stripes || ndevs < devs_min) { ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ This condition is meaningless, @devs_increment has nothing to do with @sub_stripes. In fact, in btrfs_raid_array[], profile with sub_stripes larger than 1 (RAID10) already has the @devs_increment set to 2. So no need to multiple it by @sub_stripes. And above condition is also dead. For RAID10, @devs_increment * @sub_stripes equals 4, which is also the @devs_min of RAID10. For other profiles, @sub_stripes is always 1, and since @ndevs is rounded down to @devs_increment, the condition will always be true. Remove the meaningless condition to make later reader wander less. Signed-off-by: Qu Wenruo <wqu@suse.com> Reviewed-by: Nikolay Borisov <nborisov@suse.com> Reviewed-by: David Sterba <dsterba@suse.com> Signed-off-by: David Sterba <dsterba@suse.com>
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@ -4837,13 +4837,12 @@ static int __btrfs_alloc_chunk(struct btrfs_trans_handle *trans,
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/* round down to number of usable stripes */
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/* round down to number of usable stripes */
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ndevs = round_down(ndevs, devs_increment);
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ndevs = round_down(ndevs, devs_increment);
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if (ndevs < devs_increment * sub_stripes || ndevs < devs_min) {
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if (ndevs < devs_min) {
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ret = -ENOSPC;
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ret = -ENOSPC;
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if (btrfs_test_opt(info, ENOSPC_DEBUG)) {
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if (btrfs_test_opt(info, ENOSPC_DEBUG)) {
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btrfs_debug(info,
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btrfs_debug(info,
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"%s: not enough devices with free space: have=%d minimum required=%d",
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"%s: not enough devices with free space: have=%d minimum required=%d",
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__func__, ndevs, min(devs_min,
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__func__, ndevs, devs_min);
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devs_increment * sub_stripes));
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}
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}
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goto error;
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goto error;
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}
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}
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