idr: don't need to shink the free list when idr_remove()
After idr subsystem is changed to RCU-awared, the free layer will not go to the free list. The free list will not be filled up when idr_remove(). So we don't need to shink it too. Signed-off-by: Lai Jiangshan <laijs@cn.fujitsu.com> Acked-by: Tejun Heo <tj@kernel.org> Signed-off-by: Andrew Morton <akpm@linux-foundation.org> Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
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lib/idr.c
16
lib/idr.c
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@ -18,12 +18,6 @@
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* pointer or what ever, we treat it as a (void *). You can pass this
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* id to a user for him to pass back at a later time. You then pass
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* that id to this code and it returns your pointer.
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* You can release ids at any time. When all ids are released, most of
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* the memory is returned (we keep MAX_IDR_FREE) in a local pool so we
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* don't need to go to the memory "store" during an id allocate, just
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* so you don't need to be too concerned about locking and conflicts
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* with the slab allocator.
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*/
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#ifndef TEST // to test in user space...
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@ -584,16 +578,6 @@ void idr_remove(struct idr *idp, int id)
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bitmap_clear(to_free->bitmap, 0, IDR_SIZE);
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free_layer(idp, to_free);
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}
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while (idp->id_free_cnt >= MAX_IDR_FREE) {
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p = get_from_free_list(idp);
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/*
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* Note: we don't call the rcu callback here, since the only
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* layers that fall into the freelist are those that have been
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* preallocated.
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*/
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kmem_cache_free(idr_layer_cache, p);
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}
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return;
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}
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EXPORT_SYMBOL(idr_remove);
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