mwifiex: use struct_size() in kzalloc()
One of the more common cases of allocation size calculations is finding the size of a structure that has a zero-sized array at the end, along with memory for some number of elements for that array. For example: struct foo { int stuff; struct boo entry[]; }; size = sizeof(struct foo) + count * sizeof(struct boo); instance = kzalloc(size, GFP_KERNEL) Instead of leaving these open-coded and prone to type mistakes, we can now use the new struct_size() helper: instance = kzalloc(struct_size(instance, entry, count), GFP_KERNEL) Notice that, in this case, variable regd_size is not necessary, hence it is removed. This code was detected with the help of Coccinelle. Signed-off-by: Gustavo A. R. Silva <gustavo@embeddedor.com> Signed-off-by: Kalle Valo <kvalo@codeaurora.org>
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@ -1025,17 +1025,14 @@ mwifiex_create_custom_regdomain(struct mwifiex_private *priv,
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struct ieee80211_regdomain *regd;
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struct ieee80211_reg_rule *rule;
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bool new_rule;
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int regd_size, idx, freq, prev_freq = 0;
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int idx, freq, prev_freq = 0;
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u32 bw, prev_bw = 0;
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u8 chflags, prev_chflags = 0, valid_rules = 0;
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if (WARN_ON_ONCE(num_chan > NL80211_MAX_SUPP_REG_RULES))
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return ERR_PTR(-EINVAL);
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regd_size = sizeof(struct ieee80211_regdomain) +
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num_chan * sizeof(struct ieee80211_reg_rule);
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regd = kzalloc(regd_size, GFP_KERNEL);
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regd = kzalloc(struct_size(regd, reg_rules, num_chan), GFP_KERNEL);
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if (!regd)
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return ERR_PTR(-ENOMEM);
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