Documentation, x86: Intel Memory bandwidth allocation
Update the 'intel_rdt_ui' documentation to have Memory bandwidth(b/w) allocation interface usage. Signed-off-by: Vikas Shivappa <vikas.shivappa@linux.intel.com> Cc: ravi.v.shankar@intel.com Cc: tony.luck@intel.com Cc: fenghua.yu@intel.com Cc: vikas.shivappa@intel.com Link: http://lkml.kernel.org/r/1491611637-20417-2-git-send-email-vikas.shivappa@linux.intel.com Signed-off-by: Thomas Gleixner <tglx@linutronix.de>
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@ -4,6 +4,7 @@ Copyright (C) 2016 Intel Corporation
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Fenghua Yu <fenghua.yu@intel.com>
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Tony Luck <tony.luck@intel.com>
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Vikas Shivappa <vikas.shivappa@intel.com>
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This feature is enabled by the CONFIG_INTEL_RDT_A Kconfig and the
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X86 /proc/cpuinfo flag bits "rdt", "cat_l3" and "cdp_l3".
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@ -22,19 +23,34 @@ Info directory
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The 'info' directory contains information about the enabled
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resources. Each resource has its own subdirectory. The subdirectory
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names reflect the resource names. Each subdirectory contains the
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following files:
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names reflect the resource names.
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Cache resource(L3/L2) subdirectory contains the following files:
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"num_closids": The number of CLOSIDs which are valid for this
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resource. The kernel uses the smallest number of
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CLOSIDs of all enabled resources as limit.
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"num_closids": The number of CLOSIDs which are valid for this
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resource. The kernel uses the smallest number of
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CLOSIDs of all enabled resources as limit.
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"cbm_mask": The bitmask which is valid for this resource. This
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mask is equivalent to 100%.
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"cbm_mask": The bitmask which is valid for this resource.
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This mask is equivalent to 100%.
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"min_cbm_bits": The minimum number of consecutive bits which must be
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set when writing a mask.
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"min_cbm_bits": The minimum number of consecutive bits which
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must be set when writing a mask.
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Memory bandwitdh(MB) subdirectory contains the following files:
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"min_bandwidth": The minimum memory bandwidth percentage which
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user can request.
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"bandwidth_gran": The granularity in which the memory bandwidth
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percentage is allocated. The allocated
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b/w percentage is rounded off to the next
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control step available on the hardware. The
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available bandwidth control steps are:
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min_bandwidth + N * bandwidth_gran.
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"delay_linear": Indicates if the delay scale is linear or
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non-linear. This field is purely informational
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only.
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Resource groups
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---------------
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@ -110,6 +126,22 @@ and 0xA are not. On a system with a 20-bit mask each bit represents 5%
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of the capacity of the cache. You could partition the cache into four
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equal parts with masks: 0x1f, 0x3e0, 0x7c00, 0xf8000.
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Memory bandwidth(b/w) percentage
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--------------------------------
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For Memory b/w resource, user controls the resource by indicating the
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percentage of total memory b/w.
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The minimum bandwidth percentage value for each cpu model is predefined
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and can be looked up through "info/MB/min_bandwidth". The bandwidth
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granularity that is allocated is also dependent on the cpu model and can
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be looked up at "info/MB/bandwidth_gran". The available bandwidth
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control steps are: min_bw + N * bw_gran. Intermediate values are rounded
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to the next control step available on the hardware.
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The bandwidth throttling is a core specific mechanism on some of Intel
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SKUs. Using a high bandwidth and a low bandwidth setting on two threads
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sharing a core will result in both threads being throttled to use the
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low bandwidth.
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L3 details (code and data prioritization disabled)
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--------------------------------------------------
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@ -132,6 +164,13 @@ schemata format is always:
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L2:<cache_id0>=<cbm>;<cache_id1>=<cbm>;...
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Memory b/w Allocation details
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-----------------------------
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Memory b/w domain is L3 cache.
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MB:<cache_id0>=bandwidth0;<cache_id1>=bandwidth1;...
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Reading/writing the schemata file
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---------------------------------
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Reading the schemata file will show the state of all resources
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@ -149,13 +188,14 @@ L3CODE:0=fffff;1=fffff;2=fffff;3=fffff
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Example 1
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---------
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On a two socket machine (one L3 cache per socket) with just four bits
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for cache bit masks
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for cache bit masks, minimum b/w of 10% with a memory bandwidth
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granularity of 10%
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# mount -t resctrl resctrl /sys/fs/resctrl
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# cd /sys/fs/resctrl
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# mkdir p0 p1
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# echo "L3:0=3;1=c" > /sys/fs/resctrl/p0/schemata
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# echo "L3:0=3;1=3" > /sys/fs/resctrl/p1/schemata
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# echo "L3:0=3;1=c\nMB:0=50;1=50" > /sys/fs/resctrl/p0/schemata
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# echo "L3:0=3;1=3\nMB:0=50;1=50" > /sys/fs/resctrl/p1/schemata
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The default resource group is unmodified, so we have access to all parts
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of all caches (its schemata file reads "L3:0=f;1=f").
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@ -164,6 +204,14 @@ Tasks that are under the control of group "p0" may only allocate from the
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"lower" 50% on cache ID 0, and the "upper" 50% of cache ID 1.
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Tasks in group "p1" use the "lower" 50% of cache on both sockets.
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Similarly, tasks that are under the control of group "p0" may use a
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maximum memory b/w of 50% on socket0 and 50% on socket 1.
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Tasks in group "p1" may also use 50% memory b/w on both sockets.
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Note that unlike cache masks, memory b/w cannot specify whether these
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allocations can overlap or not. The allocations specifies the maximum
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b/w that the group may be able to use and the system admin can configure
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the b/w accordingly.
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Example 2
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---------
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Again two sockets, but this time with a more realistic 20-bit mask.
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@ -177,9 +225,10 @@ of L3 cache on socket 0.
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# cd /sys/fs/resctrl
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First we reset the schemata for the default group so that the "upper"
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50% of the L3 cache on socket 0 cannot be used by ordinary tasks:
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50% of the L3 cache on socket 0 and 50% of memory b/w cannot be used by
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ordinary tasks:
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# echo "L3:0=3ff;1=fffff" > schemata
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# echo "L3:0=3ff;1=fffff\nMB:0=50;1=100" > schemata
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Next we make a resource group for our first real time task and give
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it access to the "top" 25% of the cache on socket 0.
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@ -202,6 +251,20 @@ Ditto for the second real time task (with the remaining 25% of cache):
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# echo 5678 > p1/tasks
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# taskset -cp 2 5678
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For the same 2 socket system with memory b/w resource and CAT L3 the
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schemata would look like(Assume min_bandwidth 10 and bandwidth_gran is
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10):
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For our first real time task this would request 20% memory b/w on socket
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0.
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# echo -e "L3:0=f8000;1=fffff\nMB:0=20;1=100" > p0/schemata
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For our second real time task this would request an other 20% memory b/w
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on socket 0.
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# echo -e "L3:0=f8000;1=fffff\nMB:0=20;1=100" > p0/schemata
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Example 3
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---------
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@ -215,18 +278,22 @@ the tasks.
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# cd /sys/fs/resctrl
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First we reset the schemata for the default group so that the "upper"
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50% of the L3 cache on socket 0 cannot be used by ordinary tasks:
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50% of the L3 cache on socket 0, and 50% of memory bandwidth on socket 0
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cannot be used by ordinary tasks:
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# echo "L3:0=3ff" > schemata
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# echo "L3:0=3ff\nMB:0=50" > schemata
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Next we make a resource group for our real time cores and give
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it access to the "top" 50% of the cache on socket 0.
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Next we make a resource group for our real time cores and give it access
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to the "top" 50% of the cache on socket 0 and 50% of memory bandwidth on
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socket 0.
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# mkdir p0
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# echo "L3:0=ffc00;" > p0/schemata
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# echo "L3:0=ffc00\nMB:0=50" > p0/schemata
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Finally we move core 4-7 over to the new group and make sure that the
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kernel and the tasks running there get 50% of the cache.
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kernel and the tasks running there get 50% of the cache. They should
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also get 50% of memory bandwidth assuming that the cores 4-7 are SMT
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siblings and only the real time threads are scheduled on the cores 4-7.
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# echo C0 > p0/cpus
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