scripts/gdb: provide kernel list item generators
Facilitate linked-list items by providing a generator to return the dereferenced, and type-cast objects from a kernel linked list Link: http://lkml.kernel.org/r/2b0998564e6e5abe53585d466f87e491331fd2a4.1462865983.git.jan.kiszka@siemens.com Signed-off-by: Kieran Bingham <kieran.bingham@linaro.org> Signed-off-by: Jan Kiszka <jan.kiszka@siemens.com> Cc: Jeff Mahoney <jeffm@suse.com> Signed-off-by: Andrew Morton <akpm@linux-foundation.org> Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
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@ -18,6 +18,27 @@ from linux import utils
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list_head = utils.CachedType("struct list_head")
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list_head = utils.CachedType("struct list_head")
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def list_for_each(head):
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if head.type == list_head.get_type().pointer():
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head = head.dereference()
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elif head.type != list_head.get_type():
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raise gdb.GdbError("Must be struct list_head not {}"
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.format(head.type))
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node = head['next'].dereference()
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while node.address != head.address:
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yield node.address
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node = node['next'].dereference()
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def list_for_each_entry(head, gdbtype, member):
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for node in list_for_each(head):
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if node.type != list_head.get_type().pointer():
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raise TypeError("Type {} found. Expected struct list_head *."
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.format(node.type))
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yield utils.container_of(node, gdbtype, member)
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def list_check(head):
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def list_check(head):
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nb = 0
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nb = 0
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if (head.type == list_head.get_type().pointer()):
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if (head.type == list_head.get_type().pointer()):
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