btrfs: volumes: Cleanup stripe size calculation
Cleanup the following things: 1) open coded SZ_16M round up 2) use min() to replace open-coded size comparison 3) code style Signed-off-by: Qu Wenruo <wqu@suse.com> Reviewed-by: Nikolay Borisov <nborisov@suse.com> Reviewed-by: Gu Jinxiang <gujx@cn.fujitsu.com> [ reformat comment ] Signed-off-by: David Sterba <dsterba@suse.com>
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@ -4874,18 +4874,17 @@ static int __btrfs_alloc_chunk(struct btrfs_trans_handle *trans,
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* and compare that answer with the max chunk size
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*/
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if (stripe_size * data_stripes > max_chunk_size) {
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u64 mask = (1ULL << 24) - 1;
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stripe_size = div_u64(max_chunk_size, data_stripes);
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/* bump the answer up to a 16MB boundary */
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stripe_size = (stripe_size + mask) & ~mask;
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stripe_size = round_up(stripe_size, SZ_16M);
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/* but don't go higher than the limits we found
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* while searching for free extents
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/*
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* But don't go higher than the limits we found while searching
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* for free extents
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*/
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if (stripe_size > devices_info[ndevs-1].max_avail)
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stripe_size = devices_info[ndevs-1].max_avail;
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stripe_size = min(devices_info[ndevs - 1].max_avail,
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stripe_size);
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}
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/* align to BTRFS_STRIPE_LEN */
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