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iommu/amd: Remove redundant devid checks 

Checking the return value of get_device_id() in a code-path which has
already done check_device() is not needed, as check_device() does the
same check and bails out if it fails.

Signed-off-by: Joerg Roedel <jroedel@suse.de>
Reviewed-by: Suravee Suthikulpanit <suravee.suthikulpanit@amd.com>
Link: https://lore.kernel.org/r/20200527115313.7426-11-joro@8bytes.org
This commit is contained in:
Joerg Roedel 2020-05-27 13:53:13 +02:00
parent 05a0542b45
commit 736c3333e3
1 changed files with 2 additions and 11 deletions
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13
drivers/iommu/amd_iommu.c
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@ -413,13 +413,8 @@ static void iommu_ignore_device(struct device *dev)
static void amd_iommu_uninit_device(struct device *dev) static void amd_iommu_uninit_device(struct device *dev)
{ {
struct iommu_dev_data *dev_data; struct iommu_dev_data *dev_data;
int devid;
devid = get_device_id(dev); dev_data = dev_iommu_priv_get(dev);
if (devid < 0)
return;
dev_data = search_dev_data(devid);
if (!dev_data) if (!dev_data)
return; return;
@ -2173,16 +2168,12 @@ static void amd_iommu_probe_finalize(struct device *dev)
static void amd_iommu_release_device(struct device *dev) static void amd_iommu_release_device(struct device *dev)
{ {
int devid = get_device_id(dev);
struct amd_iommu *iommu; struct amd_iommu *iommu;
int devid;
if (!check_device(dev)) if (!check_device(dev))
return; return;
devid = get_device_id(dev);
if (devid < 0)
return;
iommu = amd_iommu_rlookup_table[devid]; iommu = amd_iommu_rlookup_table[devid];
amd_iommu_uninit_device(dev); amd_iommu_uninit_device(dev);