modpost: remove is_vmlinux() helper
Now that is_vmlinux() is called only in new_module(), we can inline the function call. modname is the basename with '.o' is stripped. No need to compare it with 'vmlinux.o'. vmlinux is always located at the current working directory. No need to strip the directory path. Signed-off-by: Masahiro Yamada <masahiroy@kernel.org>
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@ -88,20 +88,6 @@ static inline bool strends(const char *str, const char *postfix)
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return strcmp(str + strlen(str) - strlen(postfix), postfix) == 0;
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}
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static int is_vmlinux(const char *modname)
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{
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const char *myname;
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myname = strrchr(modname, '/');
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if (myname)
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myname++;
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else
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myname = modname;
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return (strcmp(myname, "vmlinux") == 0) ||
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(strcmp(myname, "vmlinux.o") == 0);
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}
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void *do_nofail(void *ptr, const char *expr)
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{
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if (!ptr)
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@ -181,7 +167,7 @@ static struct module *new_module(const char *modname)
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/* add to list */
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strcpy(mod->name, modname);
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mod->is_vmlinux = is_vmlinux(modname);
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mod->is_vmlinux = (strcmp(modname, "vmlinux") == 0);
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mod->gpl_compatible = -1;
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mod->next = modules;
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modules = mod;
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