csum: Update csum_block_add to use rotate instead of byteswap
The code for csum_block_add was doing a funky byteswap to swap the even and odd bytes of the checksum if the offset was odd. Instead of doing this we can save ourselves some trouble and just shift by 8 as this should have the same effect in terms of the final checksum value and only requires one instruction. In addition we can update csum_block_sub to just use csum_block_add with a inverse value for csum2. This way we follow the same code path as csum_block_add without having to duplicate it. Signed-off-by: Alexander Duyck <aduyck@mirantis.com> Signed-off-by: David S. Miller <davem@davemloft.net>
This commit is contained in:
parent
c194cf93c1
commit
338039635d
|
@ -88,8 +88,11 @@ static inline __wsum
|
|||
csum_block_add(__wsum csum, __wsum csum2, int offset)
|
||||
{
|
||||
u32 sum = (__force u32)csum2;
|
||||
if (offset&1)
|
||||
sum = ((sum&0xFF00FF)<<8)+((sum>>8)&0xFF00FF);
|
||||
|
||||
/* rotate sum to align it with a 16b boundary */
|
||||
if (offset & 1)
|
||||
sum = ror32(sum, 8);
|
||||
|
||||
return csum_add(csum, (__force __wsum)sum);
|
||||
}
|
||||
|
||||
|
@ -102,10 +105,7 @@ csum_block_add_ext(__wsum csum, __wsum csum2, int offset, int len)
|
|||
static inline __wsum
|
||||
csum_block_sub(__wsum csum, __wsum csum2, int offset)
|
||||
{
|
||||
u32 sum = (__force u32)csum2;
|
||||
if (offset&1)
|
||||
sum = ((sum&0xFF00FF)<<8)+((sum>>8)&0xFF00FF);
|
||||
return csum_sub(csum, (__force __wsum)sum);
|
||||
return csum_block_add(csum, ~csum2, offset);
|
||||
}
|
||||
|
||||
static inline __wsum csum_unfold(__sum16 n)
|
||||
|
|
Loading…
Reference in New Issue