bpf, i386: Remove unneeded conversion to bool
The '==' expression itself is bool, no need to convert it to bool again. This fixes the following coccicheck warning: arch/x86/net/bpf_jit_comp32.c:1478:50-55: WARNING: conversion to bool not needed here arch/x86/net/bpf_jit_comp32.c:1479:50-55: WARNING: conversion to bool not needed here Signed-off-by: Jason Yan <yanaijie@huawei.com> Signed-off-by: Daniel Borkmann <daniel@iogearbox.net> Acked-by: Martin KaFai Lau <kafai@fb.com> Link: https://lore.kernel.org/bpf/20200506140352.37154-1-yanaijie@huawei.com
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@ -1475,8 +1475,8 @@ static int do_jit(struct bpf_prog *bpf_prog, int *addrs, u8 *image,
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for (i = 0; i < insn_cnt; i++, insn++) {
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const s32 imm32 = insn->imm;
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const bool is64 = BPF_CLASS(insn->code) == BPF_ALU64;
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const bool dstk = insn->dst_reg == BPF_REG_AX ? false : true;
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const bool sstk = insn->src_reg == BPF_REG_AX ? false : true;
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const bool dstk = insn->dst_reg != BPF_REG_AX;
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const bool sstk = insn->src_reg != BPF_REG_AX;
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const u8 code = insn->code;
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const u8 *dst = bpf2ia32[insn->dst_reg];
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const u8 *src = bpf2ia32[insn->src_reg];
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