sched: Remove member rt_se from struct rt_rq
It's a duplicate of tg->rt_se[cpu] and the only usage is sched_rt_rq_dequeue() and sched_rt_rq_enqueue(). After the first patch to those two function. rt_se can be removed. Signed-off-by: Yong Zhang <yong.zhang0@gmail.com> Cc: Rusty Russell <rusty@rustcorp.com.au> Signed-off-by: Peter Zijlstra <a.p.zijlstra@chello.nl> LKML-Reference: <2674af741001282258q38781619u653ca4a7dd267347@mail.gmail.com> Signed-off-by: Ingo Molnar <mingo@elte.hu>
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@ -436,7 +436,6 @@ struct rt_rq {
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struct rq *rq;
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struct list_head leaf_rt_rq_list;
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struct task_group *tg;
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struct sched_rt_entity *rt_se;
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#endif
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};
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@ -7592,7 +7591,6 @@ static void init_tg_rt_entry(struct task_group *tg, struct rt_rq *rt_rq,
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tg->rt_rq[cpu] = rt_rq;
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init_rt_rq(rt_rq, rq);
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rt_rq->tg = tg;
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rt_rq->rt_se = rt_se;
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rt_rq->rt_runtime = tg->rt_bandwidth.rt_runtime;
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if (add)
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list_add(&rt_rq->leaf_rt_rq_list, &rq->leaf_rt_rq_list);
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