mutex_lock_interruptible(): add __must_check
It's not sane to use mutex_lock_interruptible() and to then ignore the result. Ditto down_interruptible(), but I'm lazy. Cc: Ingo Molnar <mingo@elte.hu> Signed-off-by: Andrew Morton <akpm@linux-foundation.org> Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
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@ -121,11 +121,12 @@ static inline int fastcall mutex_is_locked(struct mutex *lock)
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* Also see Documentation/mutex-design.txt.
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* Also see Documentation/mutex-design.txt.
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*/
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*/
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extern void fastcall mutex_lock(struct mutex *lock);
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extern void fastcall mutex_lock(struct mutex *lock);
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extern int fastcall mutex_lock_interruptible(struct mutex *lock);
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extern int __must_check fastcall mutex_lock_interruptible(struct mutex *lock);
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#ifdef CONFIG_DEBUG_LOCK_ALLOC
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#ifdef CONFIG_DEBUG_LOCK_ALLOC
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extern void mutex_lock_nested(struct mutex *lock, unsigned int subclass);
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extern void mutex_lock_nested(struct mutex *lock, unsigned int subclass);
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extern int mutex_lock_interruptible_nested(struct mutex *lock, unsigned int subclass);
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extern int __must_check mutex_lock_interruptible_nested(struct mutex *lock,
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unsigned int subclass);
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#else
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#else
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# define mutex_lock_nested(lock, subclass) mutex_lock(lock)
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# define mutex_lock_nested(lock, subclass) mutex_lock(lock)
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# define mutex_lock_interruptible_nested(lock, subclass) mutex_lock_interruptible(lock)
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# define mutex_lock_interruptible_nested(lock, subclass) mutex_lock_interruptible(lock)
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