arm64: bpf: fix mod-by-zero case
Turns out in the case of modulo by zero in a BPF program:
A = A % X; (X == 0)
the expected behavior is to terminate with return value 0.
The bug in JIT is exposed by a new test case [1].
[1] https://lkml.org/lkml/2015/11/4/499
Signed-off-by: Zi Shen Lim <zlim.lnx@gmail.com>
Reported-by: Yang Shi <yang.shi@linaro.org>
Reported-by: Xi Wang <xi.wang@gmail.com>
CC: Alexei Starovoitov <ast@plumgrid.com>
Fixes: e54bcde3d6
("arm64: eBPF JIT compiler")
Cc: <stable@vger.kernel.org> # 3.18+
Signed-off-by: Catalin Marinas <catalin.marinas@arm.com>
This commit is contained in:
parent
251599e1d6
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@ -269,6 +269,8 @@ static int build_insn(const struct bpf_insn *insn, struct jit_ctx *ctx)
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break;
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case BPF_ALU | BPF_DIV | BPF_X:
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case BPF_ALU64 | BPF_DIV | BPF_X:
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case BPF_ALU | BPF_MOD | BPF_X:
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case BPF_ALU64 | BPF_MOD | BPF_X:
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{
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const u8 r0 = bpf2a64[BPF_REG_0];
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@ -281,16 +283,19 @@ static int build_insn(const struct bpf_insn *insn, struct jit_ctx *ctx)
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check_imm26(jmp_offset);
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emit(A64_B(jmp_offset), ctx);
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/* else */
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emit(A64_UDIV(is64, dst, dst, src), ctx);
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switch (BPF_OP(code)) {
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case BPF_DIV:
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emit(A64_UDIV(is64, dst, dst, src), ctx);
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break;
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case BPF_MOD:
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ctx->tmp_used = 1;
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emit(A64_UDIV(is64, tmp, dst, src), ctx);
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emit(A64_MUL(is64, tmp, tmp, src), ctx);
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emit(A64_SUB(is64, dst, dst, tmp), ctx);
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break;
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}
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break;
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}
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case BPF_ALU | BPF_MOD | BPF_X:
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case BPF_ALU64 | BPF_MOD | BPF_X:
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ctx->tmp_used = 1;
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emit(A64_UDIV(is64, tmp, dst, src), ctx);
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emit(A64_MUL(is64, tmp, tmp, src), ctx);
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emit(A64_SUB(is64, dst, dst, tmp), ctx);
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break;
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case BPF_ALU | BPF_LSH | BPF_X:
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case BPF_ALU64 | BPF_LSH | BPF_X:
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emit(A64_LSLV(is64, dst, dst, src), ctx);
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