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[PATCH] Kprobes ia64 qp fix 

Fix a bug where a kprobe still fires when the instruction is predicated
off.  So given the p6=0, and we have an instruction like:

(p6) move loc1=0

we should not be triggering the kprobe.  This is handled by carrying over
the qp section of the original instruction into the break instruction.

Signed-off-by: Anil S Keshavamurthy <anil.s.keshavamurthy@intel.com>
Signed-off-by: Rusty Lynch <Rusty.lynch@intel.com>
Signed-off-by: Andrew Morton <akpm@osdl.org>
Signed-off-by: Linus Torvalds <torvalds@osdl.org>
This commit is contained in:
Rusty Lynch 2005-06-23 00:09:31 -07:00 committed by Linus Torvalds
parent 8bc76772ad
commit 13608d6433
1 changed files with 3 additions and 3 deletions
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6
arch/ia64/kernel/kprobes.c
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@ -115,19 +115,19 @@ int arch_prepare_kprobe(struct kprobe *p)
case 0:
major_opcode = (bundle->quad0.slot0 >> SLOT0_OPCODE_SHIFT);
kprobe_inst = bundle->quad0.slot0;
bundle->quad0.slot0 = BREAK_INST;
bundle->quad0.slot0 = BREAK_INST | (0x3f & kprobe_inst);
break;
case 1:
major_opcode = (bundle->quad1.slot1_p1 >> SLOT1_p1_OPCODE_SHIFT);
kprobe_inst = (bundle->quad0.slot1_p0 |
(bundle->quad1.slot1_p1 << (64-46)));
bundle->quad0.slot1_p0 = BREAK_INST;
bundle->quad0.slot1_p0 = BREAK_INST | (0x3f & kprobe_inst);
bundle->quad1.slot1_p1 = (BREAK_INST >> (64-46));
break;
case 2:
major_opcode = (bundle->quad1.slot2 >> SLOT2_OPCODE_SHIFT);
kprobe_inst = bundle->quad1.slot2;
bundle->quad1.slot2 = BREAK_INST;
bundle->quad1.slot2 = BREAK_INST | (0x3f & kprobe_inst);
break;
}