MSI: Simplify BUG() handling in msi_remove_pci_irq_vectors() part 2
Although it might be nice to do a printk before BUG'ing, it's really not necessary, and it complicates the code. The behaviour has changed slightly, in that before we set a flag if the irq had an action, and continued freeing the other irqs. But as I see it that's all irrelevant because we end up BUG'ing anyway. Signed-off-by: Michael Ellerman <michael@ellerman.id.au> Acked-by: Eric W. Biederman <ebiederm@xmission.com> Signed-off-by: Greg Kroah-Hartman <gregkh@suse.de>
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@ -723,27 +723,21 @@ void msi_remove_pci_irq_vectors(struct pci_dev* dev)
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msi_free_irq(dev, dev->first_msi_irq);
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}
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if (dev->msix_enabled) {
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int irq, head, tail = 0, warning = 0;
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int irq, head, tail = 0;
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void __iomem *base = NULL;
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irq = head = dev->first_msi_irq;
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while (head != tail) {
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tail = get_irq_msi(irq)->link.tail;
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base = get_irq_msi(irq)->mask_base;
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if (irq_has_action(irq))
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warning = 1;
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else if (irq != head) /* Release MSI-X irq */
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BUG_ON(irq_has_action(irq));
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if (irq != head) /* Release MSI-X irq */
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msi_free_irq(dev, irq);
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irq = tail;
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}
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msi_free_irq(dev, irq);
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if (warning) {
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iounmap(base);
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printk(KERN_WARNING "PCI: %s: msi_remove_pci_irq_vectors() "
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"called without free_irq() on all MSI-X irqs\n",
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pci_name(dev));
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BUG_ON(warning > 0);
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}
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}
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}
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