PM / wakeup: Print warn if device gets enabled as wakeup source during sleep

In general, wakeup settings are not supposed to be changed during any of
the system wide PM phases. The reason is simply that it would break
guarantees provided by the PM core, to properly act on active wakeup
sources.

However, there are exceptions to when, in particular, disabling a device as
wakeup source makes sense. For example, in cases when a driver realizes
that its device is dead during system suspend. For these scenarios, we
don't need to care about acting on the wakeup source correctly, because a
dead device shouldn't deliver wakeup signals.

To this reasoning and to help users to properly manage wakeup settings,
let's print a warning in cases someone calls device_wakeup_enable() during
system sleep.

Suggested-by: Rafael J. Wysocki <rafael@kernel.org>
Signed-off-by: Ulf Hansson <ulf.hansson@linaro.org>
[ rjw: Message to be printed ]
Signed-off-by: Rafael J. Wysocki <rafael.j.wysocki@intel.com>

drivers/base/power/wakeup.c

@@ -19,6 +19,11 @@
 
 #include "power.h"
 
+#ifndef CONFIG_SUSPEND
+suspend_state_t pm_suspend_target_state;
+#define pm_suspend_target_state	(PM_SUSPEND_ON)
+#endif
+
 /*
  * If set, the suspend/hibernate code will abort transitions to a sleep state
  * if wakeup events are registered during or immediately before the transition.
@@ -268,6 +273,9 @@ int device_wakeup_enable(struct device *dev)
 	if (!dev || !dev->power.can_wakeup)
 		return -EINVAL;
 
+	if (pm_suspend_target_state != PM_SUSPEND_ON)
+		dev_dbg(dev, "Suspicious %s() during system transition!\n", __func__);
+
 	ws = wakeup_source_register(dev_name(dev));
 	if (!ws)
 		return -ENOMEM;