ARM: l2c: simplify l2x0 unlocking code
The l2x0 unlocking code is only called from l2x0_enable() now, so move the logic entirely into that function and simplify it. Signed-off-by: Russell King <rmk+kernel@arm.linux.org.uk>
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@ -352,30 +352,21 @@ static void l2x0_disable(void)
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raw_spin_unlock_irqrestore(&l2x0_lock, flags);
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}
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static void l2x0_unlock(u32 cache_id)
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{
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int lockregs;
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switch (cache_id & L2X0_CACHE_ID_PART_MASK) {
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case L2X0_CACHE_ID_PART_L310:
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lockregs = 8;
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break;
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default:
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/* L210 and unknown types */
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lockregs = 1;
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break;
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}
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l2c_unlock(l2x0_base, lockregs);
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}
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static void l2x0_enable(void __iomem *base, u32 aux, unsigned num_lock)
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{
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unsigned id;
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id = readl_relaxed(base + L2X0_CACHE_ID) & L2X0_CACHE_ID_PART_MASK;
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if (id == L2X0_CACHE_ID_PART_L310)
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num_lock = 8;
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else
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num_lock = 1;
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/* l2x0 controller is disabled */
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writel_relaxed(aux, base + L2X0_AUX_CTRL);
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/* Make sure that I&D is not locked down when starting */
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l2x0_unlock(readl_relaxed(base + L2X0_CACHE_ID));
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l2c_unlock(base, num_lock);
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l2x0_inv_all();
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