lib: objagg: Use struct_size() in kzalloc()
One of the more common cases of allocation size calculations is finding the size of a structure that has a zero-sized array at the end, along with memory for some number of elements for that array. For example: struct objagg_stats { ... struct objagg_obj_stats_info stats_info[]; }; size = sizeof(*objagg_stats) + sizeof(objagg_stats->stats_info[0]) * count; instance = kzalloc(size, GFP_KERNEL); Instead of leaving these open-coded and prone to type mistakes, we can now use the new struct_size() helper: instance = kzalloc(struct_size(instance, stats_info, count), GFP_KERNEL); Notice that, in this case, variable alloc_size is not necessary, hence it is removed. This code was detected with the help of Coccinelle. Signed-off-by: Gustavo A. R. Silva <gustavo@embeddedor.com> Acked-by: Jiri Pirko <jiri@mellanox.com> Signed-off-by: David S. Miller <davem@davemloft.net>
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@ -605,12 +605,10 @@ const struct objagg_stats *objagg_stats_get(struct objagg *objagg)
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{
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struct objagg_stats *objagg_stats;
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struct objagg_obj *objagg_obj;
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size_t alloc_size;
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int i;
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alloc_size = sizeof(*objagg_stats) +
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sizeof(objagg_stats->stats_info[0]) * objagg->obj_count;
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objagg_stats = kzalloc(alloc_size, GFP_KERNEL);
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objagg_stats = kzalloc(struct_size(objagg_stats, stats_info,
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objagg->obj_count), GFP_KERNEL);
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if (!objagg_stats)
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return ERR_PTR(-ENOMEM);
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