serial: mvebu-uart: correctly calculate minimal possible baudrate

For default (x16) scheme which is currently used by mvebu-uart.c driver,
maximal divisor of UART base clock is 1023*16. Therefore there is limit for
minimal supported baudrate. This change calculate it correctly and prevents
setting invalid divisor 0 into hardware registers.

Signed-off-by: Pali Rohár <pali@kernel.org>
Fixes: 68a0db1d7d ("serial: mvebu-uart: add function to change baudrate")
Link: https://lore.kernel.org/r/20210624224909.6350-4-pali@kernel.org
Signed-off-by: Greg Kroah-Hartman <gregkh@linuxfoundation.org>
This commit is contained in:
Pali Rohár 2021-06-25 00:49:02 +02:00 committed by Greg Kroah-Hartman
parent ecd6b010d8
commit deeaf96356
1 changed files with 8 additions and 3 deletions

View File

@ -481,7 +481,7 @@ static void mvebu_uart_set_termios(struct uart_port *port,
struct ktermios *old)
{
unsigned long flags;
unsigned int baud;
unsigned int baud, min_baud, max_baud;
spin_lock_irqsave(&port->lock, flags);
@ -500,16 +500,21 @@ static void mvebu_uart_set_termios(struct uart_port *port,
port->ignore_status_mask |= STAT_RX_RDY(port) | STAT_BRK_ERR;
/*
* Maximal divisor is 1023 * 16 when using default (x16) scheme.
* Maximum achievable frequency with simple baudrate divisor is 230400.
* Since the error per bit frame would be of more than 15%, achieving
* higher frequencies would require to implement the fractional divisor
* feature.
*/
baud = uart_get_baud_rate(port, termios, old, 0, 230400);
min_baud = DIV_ROUND_UP(port->uartclk, 1023 * 16);
max_baud = 230400;
baud = uart_get_baud_rate(port, termios, old, min_baud, max_baud);
if (mvebu_uart_baud_rate_set(port, baud)) {
/* No clock available, baudrate cannot be changed */
if (old)
baud = uart_get_baud_rate(port, old, NULL, 0, 230400);
baud = uart_get_baud_rate(port, old, NULL,
min_baud, max_baud);
} else {
tty_termios_encode_baud_rate(termios, baud, baud);
uart_update_timeout(port, termios->c_cflag, baud);