ima: Simplify ima_lsm_copy_rule
Currently ima_lsm_copy_rule() set the arg_p field of the source rule to NULL, so that the source rule could be freed afterward. It does not make sense for this behavior to be inside a "copy" function. So move it outside and let the caller handle this field. ima_lsm_copy_rule() now produce a shallow copy of the original entry including args_p field. Meaning only the lsm.rule and the rule itself should be freed for the original rule. Thus, instead of calling ima_lsm_free_rule() which frees lsm.rule as well as args_p field, free the lsm.rule directly. Signed-off-by: GUO Zihua <guozihua@huawei.com> Reviewed-by: Roberto Sassu <roberto.sassu@huawei.com> Signed-off-by: Mimi Zohar <zohar@linux.ibm.com>
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@ -398,12 +398,6 @@ static struct ima_rule_entry *ima_lsm_copy_rule(struct ima_rule_entry *entry)
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nentry->lsm[i].type = entry->lsm[i].type;
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nentry->lsm[i].args_p = entry->lsm[i].args_p;
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/*
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* Remove the reference from entry so that the associated
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* memory will not be freed during a later call to
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* ima_lsm_free_rule(entry).
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*/
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entry->lsm[i].args_p = NULL;
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ima_filter_rule_init(nentry->lsm[i].type, Audit_equal,
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nentry->lsm[i].args_p,
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@ -417,6 +411,7 @@ static struct ima_rule_entry *ima_lsm_copy_rule(struct ima_rule_entry *entry)
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static int ima_lsm_update_rule(struct ima_rule_entry *entry)
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{
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int i;
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struct ima_rule_entry *nentry;
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nentry = ima_lsm_copy_rule(entry);
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@ -431,7 +426,8 @@ static int ima_lsm_update_rule(struct ima_rule_entry *entry)
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* references and the entry itself. All other memory references will now
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* be owned by nentry.
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*/
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ima_lsm_free_rule(entry);
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for (i = 0; i < MAX_LSM_RULES; i++)
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ima_filter_rule_free(entry->lsm[i].rule);
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kfree(entry);
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return 0;
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