ima: Simplify ima_lsm_copy_rule

Currently ima_lsm_copy_rule() set the arg_p field of the source rule to
NULL, so that the source rule could be freed afterward. It does not make
sense for this behavior to be inside a "copy" function. So move it
outside and let the caller handle this field.

ima_lsm_copy_rule() now produce a shallow copy of the original entry
including args_p field. Meaning only the lsm.rule and the rule itself
should be freed for the original rule. Thus, instead of calling
ima_lsm_free_rule() which frees lsm.rule as well as args_p field, free
the lsm.rule directly.

Signed-off-by: GUO Zihua <guozihua@huawei.com>
Reviewed-by: Roberto Sassu <roberto.sassu@huawei.com>
Signed-off-by: Mimi Zohar <zohar@linux.ibm.com>
This commit is contained in:
GUO Zihua 2022-09-21 20:58:03 +08:00 committed by Mimi Zohar
parent 11220db412
commit d57378d3aa
1 changed files with 3 additions and 7 deletions

View File

@ -398,12 +398,6 @@ static struct ima_rule_entry *ima_lsm_copy_rule(struct ima_rule_entry *entry)
nentry->lsm[i].type = entry->lsm[i].type;
nentry->lsm[i].args_p = entry->lsm[i].args_p;
/*
* Remove the reference from entry so that the associated
* memory will not be freed during a later call to
* ima_lsm_free_rule(entry).
*/
entry->lsm[i].args_p = NULL;
ima_filter_rule_init(nentry->lsm[i].type, Audit_equal,
nentry->lsm[i].args_p,
@ -417,6 +411,7 @@ static struct ima_rule_entry *ima_lsm_copy_rule(struct ima_rule_entry *entry)
static int ima_lsm_update_rule(struct ima_rule_entry *entry)
{
int i;
struct ima_rule_entry *nentry;
nentry = ima_lsm_copy_rule(entry);
@ -431,7 +426,8 @@ static int ima_lsm_update_rule(struct ima_rule_entry *entry)
* references and the entry itself. All other memory references will now
* be owned by nentry.
*/
ima_lsm_free_rule(entry);
for (i = 0; i < MAX_LSM_RULES; i++)
ima_filter_rule_free(entry->lsm[i].rule);
kfree(entry);
return 0;