opp: Filter out OPPs based on availability of a required-OPP
A required OPP may not be available, and thus, all OPPs which are using this required OPP should be unavailable too. Tested-by: Peter Geis <pgwipeout@gmail.com> Tested-by: Nicolas Chauvet <kwizart@gmail.com> Tested-by: Matt Merhar <mattmerhar@protonmail.com> Signed-off-by: Dmitry Osipenko <digetx@gmail.com> Signed-off-by: Viresh Kumar <viresh.kumar@linaro.org>
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@ -1522,6 +1522,7 @@ int _opp_add(struct device *dev, struct dev_pm_opp *new_opp,
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struct opp_table *opp_table, bool rate_not_available)
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{
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struct list_head *head;
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unsigned int i;
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int ret;
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mutex_lock(&opp_table->lock);
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@ -1547,6 +1548,16 @@ int _opp_add(struct device *dev, struct dev_pm_opp *new_opp,
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__func__, new_opp->rate);
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}
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for (i = 0; i < opp_table->required_opp_count; i++) {
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if (new_opp->required_opps[i]->available)
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continue;
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new_opp->available = false;
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dev_warn(dev, "%s: OPP not supported by required OPP %pOF (%lu)\n",
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__func__, new_opp->required_opps[i]->np, new_opp->rate);
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break;
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}
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return 0;
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}
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