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NTB: Correctly handle receive buffers of the minimal size 

The ring logic of the NTB receive buffer/transmit memory window requires
there to be at least 2 payload sized allotments.  For the minimal size
case, split the buffer into two and set the transport_mtu to the
appropriate size.

Signed-off-by: Jon Mason <jon.mason@intel.com>
This commit is contained in:
Jon Mason 2013-02-01 15:45:16 -07:00
parent 90f9e93464
commit c9d534c8cb
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GPG Key ID: 6E664BAC7A8BD223
1 changed files with 5 additions and 3 deletions
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8
drivers/ntb/ntb_transport.c
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@ -490,11 +490,12 @@ static void ntb_transport_setup_qp_mw(struct ntb_transport *nt,
rx_size -= sizeof(struct ntb_rx_info);
qp->rx_buff = qp->remote_rx_info + 1;
qp->rx_max_frame = min(transport_mtu, rx_size);
/* Due to housekeeping, there must be atleast 2 buffs */
qp->rx_max_frame = min(transport_mtu, rx_size / 2);
qp->rx_max_entry = rx_size / qp->rx_max_frame;
qp->rx_index = 0;
qp->remote_rx_info->entry = qp->rx_max_entry;
qp->remote_rx_info->entry = qp->rx_max_entry - 1;
/* setup the hdr offsets with 0's */
for (i = 0; i < qp->rx_max_entry; i++) {
@ -818,7 +819,8 @@ static void ntb_transport_init_queue(struct ntb_transport *nt,
tx_size -= sizeof(struct ntb_rx_info);
qp->tx_mw = qp->rx_info + 1;
qp->tx_max_frame = min(transport_mtu, tx_size);
/* Due to housekeeping, there must be atleast 2 buffs */
qp->tx_max_frame = min(transport_mtu, tx_size / 2);
qp->tx_max_entry = tx_size / qp->tx_max_frame;
if (nt->debugfs_dir) {