libbpf: Fix an unsigned < 0 bug
Andrii reported a bug with the following information:
2859 if (enum64_placeholder_id == 0) {
2860 enum64_placeholder_id = btf__add_int(btf, "enum64_placeholder", 1, 0);
>>> CID 394804: Control flow issues (NO_EFFECT)
>>> This less-than-zero comparison of an unsigned value is never true. "enum64_placeholder_id < 0U".
2861 if (enum64_placeholder_id < 0)
2862 return enum64_placeholder_id;
2863 ...
Here enum64_placeholder_id declared as '__u32' so enum64_placeholder_id < 0
is always false. Declare enum64_placeholder_id as 'int' in order to capture
the potential error properly.
Fixes: f2a625889b
("libbpf: Add enum64 sanitization")
Reported-by: Andrii Nakryiko <andrii@kernel.org>
Signed-off-by: Yonghong Song <yhs@fb.com>
Signed-off-by: Daniel Borkmann <daniel@iogearbox.net>
Link: https://lore.kernel.org/bpf/20220613054314.1251905-1-yhs@fb.com
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@ -2786,7 +2786,7 @@ static int bpf_object__sanitize_btf(struct bpf_object *obj, struct btf *btf)
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bool has_decl_tag = kernel_supports(obj, FEAT_BTF_DECL_TAG);
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bool has_type_tag = kernel_supports(obj, FEAT_BTF_TYPE_TAG);
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bool has_enum64 = kernel_supports(obj, FEAT_BTF_ENUM64);
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__u32 enum64_placeholder_id = 0;
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int enum64_placeholder_id = 0;
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struct btf_type *t;
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int i, j, vlen;
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