futex: Futex_unlock_pi() determinism
The problem with returning -EAGAIN when the waiter state mismatches is that it becomes very hard to proof a bounded execution time on the operation. And seeing that this is a RT operation, this is somewhat important. While in practise; given the previous patch; it will be very unlikely to ever really take more than one or two rounds, proving so becomes rather hard. However, now that modifying wait_list is done while holding both hb->lock and wait_lock, the scenario can be avoided entirely by acquiring wait_lock while still holding hb-lock. Doing a hand-over, without leaving a hole. Signed-off-by: Peter Zijlstra (Intel) <peterz@infradead.org> Cc: juri.lelli@arm.com Cc: bigeasy@linutronix.de Cc: xlpang@redhat.com Cc: rostedt@goodmis.org Cc: mathieu.desnoyers@efficios.com Cc: jdesfossez@efficios.com Cc: dvhart@infradead.org Cc: bristot@redhat.com Link: http://lkml.kernel.org/r/20170322104152.112378812@infradead.org Signed-off-by: Thomas Gleixner <tglx@linutronix.de>
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@ -1398,15 +1398,10 @@ static int wake_futex_pi(u32 __user *uaddr, u32 uval, struct futex_pi_state *pi_
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DEFINE_WAKE_Q(wake_q);
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int ret = 0;
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raw_spin_lock_irq(&pi_state->pi_mutex.wait_lock);
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new_owner = rt_mutex_next_owner(&pi_state->pi_mutex);
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if (!new_owner) {
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if (WARN_ON_ONCE(!new_owner)) {
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/*
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* Since we held neither hb->lock nor wait_lock when coming
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* into this function, we could have raced with futex_lock_pi()
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* such that we might observe @this futex_q waiter, but the
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* rt_mutex's wait_list can be empty (either still, or again,
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* depending on which side we land).
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* As per the comment in futex_unlock_pi() this should not happen.
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*
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* When this happens, give up our locks and try again, giving
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* the futex_lock_pi() instance time to complete, either by
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@ -2794,15 +2789,18 @@ retry:
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if (pi_state->owner != current)
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goto out_unlock;
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/*
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* Grab a reference on the pi_state and drop hb->lock.
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*
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* The reference ensures pi_state lives, dropping the hb->lock
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* is tricky.. wake_futex_pi() will take rt_mutex::wait_lock to
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* close the races against futex_lock_pi(), but in case of
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* _any_ fail we'll abort and retry the whole deal.
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*/
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get_pi_state(pi_state);
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/*
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* Since modifying the wait_list is done while holding both
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* hb->lock and wait_lock, holding either is sufficient to
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* observe it.
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*
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* By taking wait_lock while still holding hb->lock, we ensure
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* there is no point where we hold neither; and therefore
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* wake_futex_pi() must observe a state consistent with what we
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* observed.
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*/
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raw_spin_lock_irq(&pi_state->pi_mutex.wait_lock);
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spin_unlock(&hb->lock);
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ret = wake_futex_pi(uaddr, uval, pi_state);
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