ice: fix potential double free in probe unrolling

If ice_init_interrupt_scheme fails, ice_probe will jump to clearing up
the interrupts. This can lead to some static analysis tools such as the
compiler sanitizers complaining about double free problems.

Since ice_init_interrupt_scheme already unrolls internally on failure,
there is no need to call ice_clear_interrupt_scheme when it fails. Add
a new unroll label and use that instead.

Signed-off-by: Jacob Keller <jacob.e.keller@intel.com>
Tested-by: Andrew Bowers <andrewx.bowers@intel.com>
Signed-off-by: Jeff Kirsher <jeffrey.t.kirsher@intel.com>
This commit is contained in:
Jacob Keller 2020-05-15 17:42:24 -07:00 committed by Jeff Kirsher
parent 072064a43e
commit bc3a024101
1 changed files with 2 additions and 1 deletions

View File

@ -3418,7 +3418,7 @@ ice_probe(struct pci_dev *pdev, const struct pci_device_id __always_unused *ent)
if (err) {
dev_err(dev, "ice_init_interrupt_scheme failed: %d\n", err);
err = -EIO;
goto err_init_interrupt_unroll;
goto err_init_vsi_unroll;
}
/* In case of MSIX we are going to setup the misc vector right here
@ -3511,6 +3511,7 @@ err_msix_misc_unroll:
ice_free_irq_msix_misc(pf);
err_init_interrupt_unroll:
ice_clear_interrupt_scheme(pf);
err_init_vsi_unroll:
devm_kfree(dev, pf->vsi);
err_init_pf_unroll:
ice_deinit_pf(pf);