kernel/gcov/gcc_3_4.c: use struct_size() in kzalloc()
One of the more common cases of allocation size calculations is finding the size of a structure that has a zero-sized array at the end, along with memory for some number of elements for that array. For example: struct foo { int stuff; void *entry[]; }; instance = kzalloc(sizeof(struct foo) + sizeof(void *) * count, GFP_KERNEL); Instead of leaving these open-coded and prone to type mistakes, we can now use the new struct_size() helper: instance = kzalloc(struct_size(instance, entry, count), GFP_KERNEL); This code was detected with the help of Coccinelle. Link: http://lkml.kernel.org/r/20190109172445.GA15908@embeddedor Signed-off-by: Gustavo A. R. Silva <gustavo@embeddedor.com> Reviewed-by: Peter Oberparleiter <oberpar@linux.ibm.com> Signed-off-by: Andrew Morton <akpm@linux-foundation.org> Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
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@ -245,8 +245,7 @@ struct gcov_info *gcov_info_dup(struct gcov_info *info)
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/* Duplicate gcov_info. */
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active = num_counter_active(info);
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dup = kzalloc(sizeof(struct gcov_info) +
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sizeof(struct gcov_ctr_info) * active, GFP_KERNEL);
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dup = kzalloc(struct_size(dup, counts, active), GFP_KERNEL);
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if (!dup)
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return NULL;
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dup->version = info->version;
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@ -364,8 +363,7 @@ struct gcov_iterator *gcov_iter_new(struct gcov_info *info)
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{
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struct gcov_iterator *iter;
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iter = kzalloc(sizeof(struct gcov_iterator) +
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num_counter_active(info) * sizeof(struct type_info),
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iter = kzalloc(struct_size(iter, type_info, num_counter_active(info)),
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GFP_KERNEL);
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if (iter)
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iter->info = info;
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