ARM: 6454/1: sa1100: Fix for a nasty initialization bug in the RTSR.
This patch fixes a nasty initialization condition on the RTSR register. Sometimes, bit 1 will wake up set, sometimes not. This can be seen by checking the value of the RTSR by typing '$ cat /proc/driver/rtc', which has been provided by the previous patch. If this bit is set, the command '$ cat /dev/rtc0' will lock the system in an endless interrupt routine calling loop. This patch fixes the issue both at sa1100_rtc_probe(), where it avoids a spurious interrupt from happening, and at sa1100_rtc_interrupt(), which is the robust solution, though it does not avoid the first spurious interrupt. Signed-off-by: Marcelo Roberto Jimenez <mroberto@cpti.cetuc.puc-rio.br> Signed-off-by: Russell King <rmk+kernel@arm.linux.org.uk>
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@ -117,7 +117,23 @@ static irqreturn_t sa1100_rtc_interrupt(int irq, void *dev_id)
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rtsr = RTSR;
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/* clear interrupt sources */
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RTSR = 0;
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RTSR = (RTSR_AL | RTSR_HZ) & (rtsr >> 2);
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/* Fix for a nasty initialization problem the in SA11xx RTSR register.
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* See also the comments in sa1100_rtc_probe(). */
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if (rtsr & (RTSR_ALE | RTSR_HZE)) {
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/* This is the original code, before there was the if test
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* above. This code does not clear interrupts that were not
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* enabled. */
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RTSR = (RTSR_AL | RTSR_HZ) & (rtsr >> 2);
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} else {
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/* For some reason, it is possible to enter this routine
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* without interruptions enabled, it has been tested with
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* several units (Bug in SA11xx chip?).
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*
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* This situation leads to an infinite "loop" of interrupt
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* routine calling and as a result the processor seems to
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* lock on its first call to open(). */
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RTSR = RTSR_AL | RTSR_HZ;
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}
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/* clear alarm interrupt if it has occurred */
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if (rtsr & RTSR_AL)
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@ -382,6 +398,30 @@ static int sa1100_rtc_probe(struct platform_device *pdev)
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platform_set_drvdata(pdev, rtc);
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/* Fix for a nasty initialization problem the in SA11xx RTSR register.
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* See also the comments in sa1100_rtc_interrupt().
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*
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* Sometimes bit 1 of the RTSR (RTSR_HZ) will wake up 1, which means an
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* interrupt pending, even though interrupts were never enabled.
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* In this case, this bit it must be reset before enabling
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* interruptions to avoid a nonexistent interrupt to occur.
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*
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* In principle, the same problem would apply to bit 0, although it has
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* never been observed to happen.
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*
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* This issue is addressed both here and in sa1100_rtc_interrupt().
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* If the issue is not addressed here, in the times when the processor
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* wakes up with the bit set there will be one spurious interrupt.
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*
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* The issue is also dealt with in sa1100_rtc_interrupt() to be on the
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* safe side, once the condition that lead to this strange
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* initialization is unknown and could in principle happen during
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* normal processing.
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*
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* Notice that clearing bit 1 and 0 is accomplished by writting ONES to
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* the corresponding bits in RTSR. */
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RTSR = RTSR_AL | RTSR_HZ;
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return 0;
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}
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