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igb: Change how we populate the RSS indirection table 

This patch cleans up our RSS indirection table configuration so that we
generate the same table regardless of CPU endianness.  In addition it
changes the table setup so that instead of doing a modulo based setup it is
instead a divisor based setup.  The advantage to this is that we should be
able to take the Rx hash and compute the Rx queue with very little CPU
overhead if needed.

Signed-off-by: Alexander Duyck <alexander.h.duyck@intel.com>
Tested-by: Aaron Brown <aaron.f.brown@intel.com>
Signed-off-by: Jeff Kirsher <jeffrey.t.kirsher@intel.com>
This commit is contained in:
Alexander Duyck 2012-09-13 06:28:11 +00:00 committed by Jeff Kirsher
parent f4128785b8
commit 797fd4be7b
1 changed files with 26 additions and 29 deletions
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55
drivers/net/ethernet/intel/igb/igb_main.c
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@ -2834,11 +2834,7 @@ static void igb_setup_mrqc(struct igb_adapter *adapter)
{
struct e1000_hw *hw = &adapter->hw;
u32 mrqc, rxcsum;
u32 j, num_rx_queues, shift = 0, shift2 = 0;
union e1000_reta {
u32 dword;
u8 bytes[4];
} reta;
u32 j, num_rx_queues, shift = 0;
static const u8 rsshash[40] = {
0x6d, 0x5a, 0x56, 0xda, 0x25, 0x5b, 0x0e, 0xc2, 0x41, 0x67,
0x25, 0x3d, 0x43, 0xa3, 0x8f, 0xb0, 0xd0, 0xca, 0x2b, 0xcb,
@ -2856,35 +2852,36 @@ static void igb_setup_mrqc(struct igb_adapter *adapter)
num_rx_queues = adapter->rss_queues;
if (adapter->vfs_allocated_count) {
/* 82575 and 82576 supports 2 RSS queues for VMDq */
switch (hw->mac.type) {
case e1000_i350:
case e1000_82580:
num_rx_queues = 1;
shift = 0;
break;
case e1000_82576:
switch (hw->mac.type) {
case e1000_82575:
shift = 6;
break;
case e1000_82576:
/* 82576 supports 2 RSS queues for SR-IOV */
if (adapter->vfs_allocated_count) {
shift = 3;
num_rx_queues = 2;
break;
case e1000_82575:
shift = 2;
shift2 = 6;
default:
break;
}
} else {
if (hw->mac.type == e1000_82575)
shift = 6;
break;
default:
break;
}
for (j = 0; j < (32 * 4); j++) {
reta.bytes[j & 3] = (j % num_rx_queues) << shift;
if (shift2)
reta.bytes[j & 3] |= num_rx_queues << shift2;
if ((j & 3) == 3)
wr32(E1000_RETA(j >> 2), reta.dword);
/*
* Populate the indirection table 4 entries at a time. To do this
* we are generating the results for n and n+2 and then interleaving
* those with the results with n+1 and n+3.
*/
for (j = 0; j < 32; j++) {
/* first pass generates n and n+2 */
u32 base = ((j * 0x00040004) + 0x00020000) * num_rx_queues;
u32 reta = (base & 0x07800780) >> (7 - shift);
/* second pass generates n+1 and n+3 */
base += 0x00010001 * num_rx_queues;
reta |= (base & 0x07800780) << (1 + shift);
wr32(E1000_RETA(j), reta);
}
/*