btrfs: abort transaction at balance_level() when left child is missing
At balance_level() we are calling btrfs_handle_fs_error() when the middle child only has 1 item and the left child is missing, however we can simply use btrfs_abort_transaction(), which achieves the same purposes: to turn the fs to error state, abort the current transaction and turn the fs to RO mode. Besides that, btrfs_abort_transaction() also prints a stack trace which makes it more useful. Also, as this is a highly unexpected case and it's about a b+tree inconsistency, change the error code from -EROFS to -EUCLEAN, tag the if branch as 'unlikely' and log an explicit error message. Reviewed-by: Qu Wenruo <wqu@suse.com> Signed-off-by: Filipe Manana <fdmanana@suse.com> Reviewed-by: David Sterba <dsterba@suse.com> Signed-off-by: David Sterba <dsterba@suse.com>
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@ -1164,9 +1164,13 @@ static noinline int balance_level(struct btrfs_trans_handle *trans,
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* otherwise we would have pulled some pointers from the
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* right
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*/
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if (!left) {
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ret = -EROFS;
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btrfs_handle_fs_error(fs_info, ret, NULL);
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if (unlikely(!left)) {
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btrfs_crit(fs_info,
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"missing left child when middle child only has 1 item, parent bytenr %llu level %d mid bytenr %llu root %llu",
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parent->start, btrfs_header_level(parent),
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mid->start, btrfs_root_id(root));
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ret = -EUCLEAN;
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btrfs_abort_transaction(trans, ret);
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goto out;
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}
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wret = balance_node_right(trans, mid, left);
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