fanotify: Fix the checks in fanotify_fsid_equal
Clang warns:
fs/notify/fanotify/fanotify.c:28:23: warning: self-comparison always
evaluates to true [-Wtautological-compare]
return fsid1->val[0] == fsid1->val[0] && fsid2->val[1] == fsid2->val[1];
^
fs/notify/fanotify/fanotify.c:28:57: warning: self-comparison always
evaluates to true [-Wtautological-compare]
return fsid1->val[0] == fsid1->val[0] && fsid2->val[1] == fsid2->val[1];
^
2 warnings generated.
The intention was clearly to compare val[0] and val[1] in the two
different fsid structs. Fix it otherwise this function always returns
true.
Fixes: afc894c784
("fanotify: Store fanotify handles differently")
Link: https://github.com/ClangBuiltLinux/linux/issues/952
Link: https://lore.kernel.org/r/20200327171030.30625-1-natechancellor@gmail.com
Signed-off-by: Nathan Chancellor <natechancellor@gmail.com>
Reviewed-by: Nick Desaulniers <ndesaulniers@google.com>
Signed-off-by: Jan Kara <jack@suse.cz>
This commit is contained in:
parent
44d705b037
commit
6def1a1d2d
|
@ -25,7 +25,7 @@ static bool fanotify_path_equal(struct path *p1, struct path *p2)
|
|||
static inline bool fanotify_fsid_equal(__kernel_fsid_t *fsid1,
|
||||
__kernel_fsid_t *fsid2)
|
||||
{
|
||||
return fsid1->val[0] == fsid1->val[0] && fsid2->val[1] == fsid2->val[1];
|
||||
return fsid1->val[0] == fsid2->val[0] && fsid1->val[1] == fsid2->val[1];
|
||||
}
|
||||
|
||||
static bool fanotify_fh_equal(struct fanotify_fh *fh1,
|
||||
|
|
Loading…
Reference in New Issue