x86: Select CONFIG_HAVE_IRQ_EXIT_ON_IRQ_STACK
Now that all invocations of irq_exit_rcu() happen on the irq stack, turn on CONFIG_HAVE_IRQ_EXIT_ON_IRQ_STACK which causes the core code to invoke __do_softirq() directly without going through do_softirq_own_stack(). That means do_softirq_own_stack() is only invoked from task context which means it can't be on the irq stack. Remove the conditional from run_softirq_on_irqstack_cond() and rename the function accordingly. Signed-off-by: Thomas Gleixner <tglx@linutronix.de> Reviewed-by: Kees Cook <keescook@chromium.org> Link: https://lore.kernel.org/r/20210210002513.068033456@linutronix.de
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@ -187,6 +187,7 @@ config X86
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select HAVE_HW_BREAKPOINT
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select HAVE_IDE
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select HAVE_IOREMAP_PROT
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select HAVE_IRQ_EXIT_ON_IRQ_STACK if X86_64
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select HAVE_IRQ_TIME_ACCOUNTING
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select HAVE_KERNEL_BZIP2
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select HAVE_KERNEL_GZIP
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@ -189,19 +189,16 @@
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"call %P[__func] \n"
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/*
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* Macro to invoke __do_softirq on the irq stack. Contrary to the above
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* the only check which is necessary is whether the interrupt stack is
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* in use already.
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* Macro to invoke __do_softirq on the irq stack. This is only called from
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* task context when bottom halfs are about to be reenabled and soft
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* interrupts are pending to be processed. The interrupt stack cannot be in
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* use here.
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*/
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#define run_softirq_on_irqstack_cond() \
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#define run_softirq_on_irqstack() \
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{ \
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if (__this_cpu_read(hardirq_stack_inuse)) { \
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__do_softirq(); \
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} else { \
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__this_cpu_write(hardirq_stack_inuse, true); \
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call_on_irqstack(__do_softirq, ASM_CALL_SOFTIRQ); \
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__this_cpu_write(hardirq_stack_inuse, false); \
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} \
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__this_cpu_write(hardirq_stack_inuse, true); \
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call_on_irqstack(__do_softirq, ASM_CALL_SOFTIRQ); \
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__this_cpu_write(hardirq_stack_inuse, false); \
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}
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#else /* CONFIG_X86_64 */
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@ -76,5 +76,5 @@ int irq_init_percpu_irqstack(unsigned int cpu)
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void do_softirq_own_stack(void)
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{
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run_softirq_on_irqstack_cond();
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run_softirq_on_irqstack();
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}
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